logoChat01.ai

Question

IMG20260124142536.jpgIMG20260124142536.jpg
IMG20260124142548.jpgIMG20260124142548.jpg

Solution cpp

Thought

Implementing functions for matrix problem

I’m tackling a problem where I need to implement several functions like getZValue, getRowColSumOfElement, isprime, and PrimeFactors. The matrix has unique integers and I need to find the location of an element, compute row and column sums, and use modular arithmetic for wrap-around behavior. Let’s work through this!

Handling problem details and edge cases

The problem requires me to handle wrap-around rows and print prime factors for an element Z. Edge cases include whether Z can be negative or if it's 1—prime factors of 1 are none. I'll assume Z is positive for now and handle it accordingly. I should provide a full C++ solution with the missing functions filled in.

Clarifying the template and function roles

The template includes necessary libraries like <string.h>, <math.h>, and <iostream>. I'll focus on the getZValue function, which computes the row of Z based on its description. For getRowColSumOfElement, I'll locate element X and return the sum. The isprime function checks primes, while PrimeFactors uses trial division to find prime factors, then prints them in ascending order.

Prime factors handling and approach for Z

If Z is prime, I'll just output it; if not, I’ll print its factors, including repetitions, as that's the usual prime factor output format. I'll handle negative numbers by factoring the absolute value and including a "-1" if necessary. Additionally, for zero, prime factors aren't defined, so we’ll skip it. The output format expects prime factors on a second line, separated by spaces.

Prime factor printing and code structure considerations

For prime factors, I’ll make sure to print them separated by single spaces without trailing spaces. If Z is prime, I’ll store {Z} in the vector. If Z is 1, I’ll print 1, since prime factors aren't defined for 1, but we need something. The isprime function will handle checking for values ≤ 1 and then check for smaller primes up to 35. I'll stick to the template format while avoiding strict dependencies on global variables and external libraries. I’ll ensure compatibility for easy copy-pasting.

Thought for 1m 18s

Answer

cpp
#include <iostream>
#include <vector>
using namespace std;

int row, col, n;
int a[100][100];

int getZValue(int s) // s = row + col of X
{
    int k = row;
    s %= n; // moving up by n gives same row
    for (int i = 0; i < s; i++) {
        k--;
        if (k < 0) k = n - 1; // wrap to last row
    }
    return a[k][col];
}

int getRowColSumOfElement(int x) // find X and set row,col
{
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (a[i][j] == x) {
                row = i;
                col = j;
                return row + col;
            }
        }
    }
    row = col = 0; // (X will always exist as per problem)
    return 0;
}

bool isprime(int x)
{
    if (x < 2) return false;
    if (x % 2 == 0) return x == 2;
    for (int d = 3; 1LL * d * d <= x; d += 2) {
        if (x % d == 0) return false;
    }
    return true;
}

void PrimeFactors(int x)
{
    long long v = x;
    vector<long long> f;

    if (v == 0) { // not expected, but keeps output defined
        cout << 0;
        return;
    }

    if (v < 0) { // just in case negatives appear
        f.push_back(-1);
        v = -v;
    }

    if (v == 1) {
        f.push_back(1);
    } else {
        for (long long p = 2; p * p <= v; ++p) {
            while (v % p == 0) {
                f.push_back(p);
                v /= p;
            }
        }
        if (v > 1) f.push_back(v);
    }

    for (size_t i = 0; i < f.size(); i++) {
        if (i) cout << " ";
        cout << f[i];
    }
}

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    cin >> n;
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++)
            cin >> a[i][j];

    int x;
    cin >> x;

    int s = getRowColSumOfElement(x);
    int z = getZValue(s);

    cout << z << "\n";
    PrimeFactors(z);
    cout << "\n";
    return 0;
}

Share this Q&A