小鼠Y染色体上的S基因决定雄性性别的发生,在X染色体上无等位基因,带有S基因的染色体片段可转接到X染...
Created on: February 4, 2025
Created on: February 4, 2025
小鼠Y染色体上的S基因决定雄性性别的发生,在X染色体上无等位基因,带有S基因的染色体片段可转接到X染色体上。已知配子形成不受S基因位置和数量的影响,染色体能正常联会、分离,产生的配子均具有受精能力;含S基因的受精卵均发育为雄性,不含S基因的均发育为雌性,但含有两个Y染色体的受精卵不发育。一个基因型为XYS的受精卵中的S基因丢失,由该受精卵发育成能产生可育雌配子的小鼠。若该小鼠与一只体细胞中含两条性染色体但基因型未知的雄鼠杂交得F1,F1小鼠雌雄间随机杂交得F2,则F2小鼠中雌雄比例可能为() A. 4: 3 B. 3: 4 C. 8: 3 D. 7: 8
Examining genetics
I’m looking into how an XYS genotype results in a female mouse once the S gene is lost, leading to the production of viable female gametes.
Assessing genetic patterns
I’m pinpointing the female's genotype, with suggestions pointing to XY. This female, due to the lack of the S gene, is phenotypically female and typically can't produce male offspring.
Mapping out the genes
Tracing the female's XY genotype and unseen male genotype to spot male-to-female ratios, considering factors like the S gene on the X chromosome.
Assessing the father's genotype
OK, let's think it through: the father likely has at least one S gene. This leads to considering possibilities like XY^S, X^S X, or X^S Y^S, while ruling out certain combinations.
Mapping out male patterns
I’m thinking through the possibilities for male genotypes: XY^S, X^S X, and X^S Y^S, steering clear of combinations like Y^S Y^S.
Focusing on sex chromosomes
I'm pulling together the father’s genotype, considering combinations like XY^S and X^S X, while mindful of 2 Y chromosomes being unviable.
Weighing possibilities
I'm collecting info on genotypes and the father: XYS and X^S Y look promising. X^S Y^S is a non-starter due to its lethal implications.
Debunking the theory
OK, let's see. The X^S Y^S genotype works since only one Y chromosome is present, making fatal complications unlikely. Other conditions like Y^S Y^S and X^S X^S are avoided.
Taking a closer look
I'm starting to see that X^S X^S might be plausible if the two X chromosomes don't cause inviability. Other genotypes like X^S Y and Y^S X are also potentially viable.
Piecing together
I’m thinking the mother’s genotype is X Y, with the S gene lost. Normally, XY is male with S, so this female development is intriguing.
Examining the Y chromosome
I’m curious about the mother’s Y chromosome without the S gene, which still lets her produce viable female gametes, as viable gametes emerge as X or Y.
Piecing it together
Shifting my focus to the mother’s ability to produce both X and Y gametes, which is unusual yet follows the problem's logic. The father must carry at least one S chromosome.
Mapping the options
I’m listing each crossing possibility between the mother and father, aiming to pinpoint the correct male to female ratio among the F2 mice. It’s interesting to see where this leads.
Analyzing fertilization
I’m thinking through how the mother’s and father’s gametes combine, considering viability by removing any potential deformations or inviable combinations, and then examining the resulting F1 and F2 generations.
Tracking gene impact
I’m suggesting a simpler method: analyzing the S gene distribution in the population and examining how the mother’s Y gametes and the father’s Y^S gametes influence the F2 sex ratio.
Assessing genotype outcomes
I’m mapping out the distribution of genotypes and sex determination for F1 and F2 generations, using a standard XY^S father and a mother with X Y genotypes.
Analyzing gamete combinations
I’m examining how the mother’s X and Y gametes combine with the father’s X and Y^S gametes, resulting in viable male and female F1 zygotes.
Ratios among viable F1
I’m thinking through the survival rate of F1 zygotes, excluding the lethal combination, and finding the genotypic ratio among the viable ones to be 1:1:1.
Examining gender ratio
I’m noting the gender ratio of F1 progeny from a XY^S father: 2/3 female and 1/3 male, considering the viable genotypes XX, X Y^S, and X Y.
Analyzing F1 mating
Considering female F1 genotypes (XX and XY) and male F1 genotype (XY^S). Female F1 split equally into XX and XY, each 1/3.
Assessing mating dynamics
Females (XX and XY) mate with males (XY^S). With a 2:1 female to male ratio, each male pairs with 2 females on average.
Assessing F2 outcomes
First, half of F2 zygotes are female (XX), the other half male (XY^S). This trend might continue, but let me see further.
Evaluating gamete possibilities
Crossing XY females with XY^S males reveals three viable F2 zygote outcomes: XX (female), XY^S (male), and XY (female), each with a 1/4 chance.
Tracking outcomes
OK, focusing on the critical 3/4 probability for survival, observing a 2:1 female to male ratio among the viable offspring. This makes me think about selection impacts.
Analyzing mating dynamics
I’m weighing the likelihood of XX and XY^S males for Cross 1, then XY females and XY^S males for Cross 2. Random mating ratios could tilt the scales.
Mapping mating dynamics
OK, let’s look at N F1 individuals where 1/3 are XX females, 1/3 are XY females, and 1/3 are XY^S males. Considering random pairing within these groups.
Calculating mating odds
Interestingly enough, with a 1/2 chance of picking XX or XY females, each cross is equally likely. The sex ratio from Cross 1 remains 1:1.
Balancing ratios
Taking a closer look at Cross 1 and Cross 2, each contributing 2k offspring, the combined sex ratio averages out to a balanced 1:1. Progressing through the calculations reveals more clarity.
Breaking down ratios
OK, I’m thinking through the ratio of 2:1 in Cross 2. This leads me to conclude that among 2k offspring, 2/3 are female and 1/3 are male.
Weighing the odds
I'm thinking through the fractions of XX and XY females from a 1/3 ratio, comparing this with the total weighting, and noting the absence of 7:5 in the answer choices.
Mapping out mating odds
OK, let me see. I’m calculating the probability of different pairs within the population and aligning the resulting sex ratios with the provided options to check for congruence.
Refining details
Let's refine the sex ratio, considering cross 2's 1/4 lethal chance, leading to a 3/4 survival and revealing the struggle to match a finite ratio from discrete outcomes.
Mapping out offspring
I'm calculating the total number of litters and their composition by considering the ratio of XX and XY females to XY^S males, keeping in mind the likelihood of each offspring type.
Mapping out the pairing process
I'm detailing the pairing of XX and XY females with XY^S males, ensuring equal mating capacity and averaging offspring per mating to simplify the calculation.
Evaluating potential outcomes
I'm thinking through the expected number of surviving offspring per cross, defined as 1 for simplicity, and exploring the probability of each sex ratio outcome from the offspring.
Piecing it together
I’m examining expected surviving offspring and their sex ratios for both cross types. Cross 1 has a 1:1 ratio, while Cross 2 has a 2:1 ratio with 3/4 surviving children.
Calculating total offspring
First, I’m figuring out the N/3 type 1 matings producing N/6 females and N/6 males. Then, adding type 2 matings, I get N/6 females and N/12 males from N/4 offspring.
Summing up offspring
OK, let me see. I’m balancing the male-to-female ratio, which is 4:3, aligning with the provided answer choices for the scenario. It's interesting to see the ratio match.
Reasoned for 10m 19s
分析思路概要:
题目给出的关键信息可以归纳为:
S 基因决定雄性:
母鼠的基因型:
父鼠的基因型仅知“含两条性染色体且能表现为雄性”:
下面先以父鼠 = X Y^S为例,详细推导 F_2 的雌雄比例。若能得到与选项对应的结果,则可直接判断答案。
母方配子(X Y^- 雌鼠):
父方配子(X Y^S 雄鼠):
将这两方配子两两组合,得到的合子类型及其命运如下表:
母方\父方 | X (1/2) | Y^S (1/2) |
---|---|---|
X (1/2) | XX(雌) | X Y^S(雄) |
Y^- (1/2) | X Y^-(雌) | Y^- Y^S(不发育) |
Y^- + Y^S
由于含有 两条 Y,不发育。因此,F_1 能正常出生的后代中,雌雄比例 = 2 : 1,具体为
- 2/3 雌(XX 或 X Y^-),
- 1/3 雄(X Y^S)。
F_1 中能存活的个体里:
F_2 是让这些 F_1 的雌雄随机交配后所生。由于 F_1 只有一种雄鼠基因型(X Y^S),雌鼠则有两种 (XX 或 X Y^-)。我们分两类交配来讨论:
于是合子类型:
该类交配的后代雌雄比 = 1 : 1 (且都能存活)。
组合如下表:
母方\父方 | X (1/2) | Y^S (1/2) |
---|---|---|
X (1/2) | XX(雌) | X Y^S(雄) |
Y^- (1/2) | X Y^-(雌) | Y^- Y^S(不发育) |
Y^- Y^S
不发育(双 Y)。在 F_1 群体里:
记“每对交配平均产生 N 个受精卵”:
XX × X Y^S 这类交配:
X Y^- × X Y^S 这类交配:
两种交配各占一半时,总体来看(把两类加起来):
因此,F_2 存活后代的 雌 : 雄 = N : (3N/4) = 4 : 3。
题目中给出的四个比值选项分别是:
A. 4 : 3
B. 3 : 4
C. 8 : 3
D. 7 : 8
由以上分析可知,当父鼠是较“常规”的 X Y^S 型雄鼠时,最终 F_2 的雌雄比会是 4 : 3。故正确答案即为:
A. 4 : 3
根据典型且最简便的父本基因型 X Y^S 分析,F_2 最终能够出现的雌雄比例为 4 : 3。故答案选择 A。