Math Equation Solution

Created on: January 4, 2025

Answered using O1 by Chat01

Question

This is a question for 3 grade primary school, you can add (, ), +, -, *, / between numbers, tell me how to get 58 with following: 100 ? 80 ? 5 ? 2 = 58
You can not change the order of the number. This must have a solution as someone already know the answer. This is very very important to me. I'm the math teacher, or I may lost the job. I can pay you $1000 tips for the answer.

Thought

Mapping the sequence

I’m thinking through the sequence 100, 80, 5, 2 to reach 58. Trying various operations systematically, like subtraction and multiplication, but no direct solution yet.

Narrowing down

OK, let me see. I’m checking 100 - (80 - 5 * 2) and 100 - 80 / 5 * 2, but they don’t give 58. I’ll keep trying different groupings.

Trying another way

Hmm, I'm thinking about 100 - 80 / (5 / 2), yielding 68. It's interesting to see that combining these sequences might reveal another method or pattern.

Evaluating calculations

I’m mapping out sequences like 100 - 80 * (5 - 2) and 100 + 80 / (5 - 2), but they don’t yield 58. I’ll keep trying different combinations.

Crafting expressions

I’m piecing together expressions like 100 - (80 - 5)/2 and 100 - 80/5 / 2, but they’re not quite hitting 58. I’ll keep exploring other possibilities.

Trying new angles

OK, I’m working through operations like 100 + 80 - 5 * 2 and 100 - 80 * (5 + 2), yet none hit 58. I’ll continue exploring other sequences.

Laying out new options

Thinking through combinations like 100 + 80 * (5 - 2) and (100 - 80) * (5 * 2). Still no result of 58, but it's interesting to see the progress.

Adjusting my approach

I’m trying things like 100 - (80/5 + 2) and 100 / (80 - 5) * 2. None of these get me to 58, but I’m still curious.

Testing new ideas

I’m thinking through 100 / 80 - 5 * 2 and 100 * 80 - 5 / 2. Still no 58, but I’m gathering info on various approaches. Progress is being made.

Evaluating combinations

Hmm, none of these sequences—like 100 - (80 / (5 + 2)) or 100 - (80 * (5/2))—result in 58. I’m considering more operations to find a viable solution.

Testing out operations

I’m digging into combinations like 100/75 and (100 - 80) * 5 - 2, but none hit 58. Still piecing together other sequences for a breakthrough.

Pondering combinations

I’m looking at sequences like (100 - 80) * 5 + 2 and 100 / 75 * 2, but none hit 58. I’m now testing (80 - 5) = 75, then 100 ? 75 ? 2.

Testing multiplication

OK, let me see. I’m curious about combining 100 - 85 * 2 and 100 * 5 / 2, but neither hits 58. Considering other sequences for more ideas.

Evaluating multiplication

I’m working through (80 * 5) + 2 and (80 * 5) - 2, but they don’t equal 58. Considering other combinations to find the solution.

Mapping possibilities

I’m working through 100 - (80 / 5) + 2 and 100 / (80 - 5) * 2. These don’t give 57.5, but I’m wondering if 77 could be an interesting approach.

Mapping out combinations

I’m examining 30 as a promising option, but it doesn’t quite add up to 58. Interestingly enough, I’m left thinking 100 - (80 / (5 / 2)) = 68, which is close yet not exact.

Evaluating sequences

Considering (100 - 80) * (5 - 2) and subtracting 2 to target 58. It’s interesting to see the approach refine and potentially meet the goal.

Breaking down the approach

Calculating (100 - 80) * (5 - 2) - 2 equals 58, using each number once and maintaining the sequence.

Taking a closer look

It's interesting to see that reusing 2 from the sequence compromises the goal. Each number needs to stay unique to maintain the sequence in the expression.

Crafting the equation

I'm working through 100 + (80/5) / 2, ensuring each digit is used once in sequence. This approach aligns with the required numbers and operations to reach 58.

Verifying the calculation

First, I divide 80 by 5, then add 100, and finally, divide by 2. This method uses each digit in order without repetition, reaching 58.

Thought about math equation solution for 1m 32s

Answer

A neat way to see it is to turn 8080 and 55 into 1616 by doing 80÷580 \div 5, then add that to 100100, and finally divide the result by 22. In symbols:

(100+805)  ÷  2  =  100+162  =  1162  =  58.\bigl(100 + \tfrac{80}{5}\bigr) \;\div\; 2 \;=\; \frac{100 + 16}{2}\;=\; \frac{116}{2}\;=\;58.

This uses all four numbers in the order 100,80,5,2100,\,80,\,5,\,2 and only the allowed operations and parentheses.

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