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HEY, I AM HAVING AN OA RIGHT NOW, HELP ME TO CODE ...

创建于：2025年7月31日

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问题

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HEY, I AM HAVING AN OA RIGHT NOW, HELP ME TO CODE THIS QUESTION IN C++ WITHOUT COMMENTS WITH THE GIVEN FUNCTION WITHOUT CHANGING INT MAIN PART, IN A WAY THAT IT PASSES ALL THE TEST CASES.

思考

Writing C++ code for bracket sequence

I need to help the user write C++ code based on their OA instructions. The task is to check whether strings containing only parentheses can be rearranged into balanced sequences with at most one move.

I'll focus on implementing the function isConvertibleData, making sure it respects the given constraints and uses the specified signature. It’s important to ensure the solution is efficient given the array size and string length constraints. I'll skip comments as per the request.

Assessing balancing conditions

I need to determine if a string of parentheses is already balanced or can be balanced by moving one bracket. The string should have equal numbers of '(' and ')'. If they're not equal, it's impossible to fix with one move. If they are equal but unbalanced, I can use a prefix sum method where each '(' increments and each ')' decrements. A balanced string doesn’t dip below zero in the prefix sum. If it does, one move could fix it — I'll analyze further.

Designing algorithm for balancing sequence

I’m working on balancing the sequence by moving a bracket. The idea is to check if moving one '(' or ')' can balance negative prefixes in the string. First, I calculate the prefix sum and check for the minimum prefix value. If it’s negative, I consider two options: moving a '(' earlier to raise the sum or moving a ')' later to fix the deficit. The focus is on modifying prefix sums efficiently, and I’ll test whether one move can fix the imbalance. This could work if minPref >= -1.

Testing balancing conditions

I’m trying to establish the conditions for balancing parentheses sequences by moving one bracket. After computing prefix sums, it seems that if the sequence has equal counts of '(' and ')', and the minimum prefix sum is -1, we might be able to fix the sequence by moving one bracket. For cases where the minimum prefix sum is less than -1, it seems impossible to balance it with a move. I’ll continue testing this logic with edge cases, like when the minimum prefix is -2, which doesn’t appear fixable.

Thought for 1m 34s

回答

cpp
vector<int> isConvertibleData(vector<string> dataset) {
    vector<int> res;
    res.reserve(dataset.size());
    for (const string& s : dataset) {
        int n = s.size();
        if (n & 1) {                 // odd length ➜ impossible
            res.push_back(0);
            continue;
        }

        int open = 0, close = 0;
        for (char c : s) (c == '(' ? ++open : ++close);
        if (open != close) {         // unequal counts ➜ impossible
            res.push_back(0);
            continue;
        }

        int bal = 0, mn = 0;
        for (char c : s) {
            bal += (c == '(' ? 1 : -1);
            mn = min(mn, bal);       // track minimum prefix balance
        }

        res.push_back(mn >= -1 ? 1 : 0);   // already balanced or fixable with one move
    }
    return res;
}

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