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I AM HAVING AN OA RIGHT NOW HELP ME TO CODE THIS Q...

创建于：2025年7月30日

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问题

2.4.jpg
2.5.jpg
2.2.jpg
2.3.jpg
2.1.jpg

I AM HAVING AN OA RIGHT NOW HELP ME TO CODE THIS QUESTION IN C++ WITHOUT COMMENTS IN A WAY THAT IT PASSES ALL THE TEST CASES AND START THE CODE WITH THE FUNCTION GIVEN IN A CODE WITHOUT CHANGING THE INT MAIN PART

Python

python
from PIL import Image
import matplotlib.pyplot as plt

img = Image.open('/mnt/data/2.1.jpg')
plt.imshow(img); plt.axis('off')

(-0.5, 959.5, 1279.5, -0.5)

Python

python
img = Image.open('/mnt/data/2.2.jpg')
plt.imshow(img); plt.axis('off')

(-0.5, 959.5, 1279.5, -0.5)

Python

python
img = Image.open('/mnt/data/2.3.jpg')
plt.imshow(img); plt.axis('off')

(-0.5, 959.5, 1279.5, -0.5)

Python

python
img = Image.open('/mnt/data/2.4.jpg')
plt.imshow(img); plt.axis('off')

(-0.5, 959.5, 1279.5, -0.5)

Python

python
img = Image.open('/mnt/data/2.5.jpg')
plt.imshow(img); plt.axis('off')

(-0.5, 959.5, 1279.5, -0.5)

Python

python
def canReach(x1,y1,x2,y2):
    sx,sy=x1,y1
    tx,ty=x2,y2
    while tx>=sx and ty>=sy:
        if tx==sx and ty==sy:
            return True
        if tx==ty:
            break
        if tx>ty:
            if ty>sy:
                tx%=ty
                if tx==0:
                    tx=ty
            else:
                return (tx-sx)%ty==0
        else:
            if tx>sx:
                ty%=tx
                if ty==0:
                    ty=tx
            else:
                return (ty-sy)%tx==0
    return tx==sx and ty==sy

print(canReach(1,4,5,9))
print(canReach(1,1,5,5))

Python

python
print(canReach(1,1,3,2))

Python

python
print(canReach(1,1,1000000000,1))

Python

python
print(canReach(2,4,5,6))

思考

Finalizing code

The user requested a final, clean version of the code without any explanations or comments. I’ll just provide the C++ code for the canReach function directly as requested:

cpp
string canReach(int x1, int y1, int x2, int y2) {
    long long sx = x1, sy = y1, tx = x2, ty = y2;
    while (tx >= sx && ty >= sy) {
        if (tx == sx && ty == sy) return "Yes";
        if (tx == ty) break;
        if (tx > ty) {
            if (ty > sy) tx %= ty;
            else return ((tx - sx) % ty == 0) ? "Yes" : "No";
        } else {
            if (tx > sx) ty %= tx;
            else return ((ty - sy) % tx == 0) ? "Yes" : "No";
        }
    }
    return (tx == sx && ty == sy) ? "Yes" : "No";
}

Thought for 1m 50s

回答

cpp
string canReach(int x1, int y1, int x2, int y2) {
    long long sx = x1, sy = y1, tx = x2, ty = y2;
    while (tx >= sx && ty >= sy) {
        if (tx == sx && ty == sy) return "Yes";
        if (tx == ty) break;
        if (tx > ty) {
            if (ty > sy) {
                tx %= ty;
                if (tx == 0) tx = ty;
            } else {
                return ((tx - sx) % ty == 0) ? "Yes" : "No";
            }
        } else {
            if (tx > sx) {
                ty %= tx;
                if (ty == 0) ty = tx;
            } else {
                return ((ty - sy) % tx == 0) ? "Yes" : "No";
            }
        }
    }
    return (tx == sx && ty == sy) ? "Yes" : "No";
}

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