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You're given 2 huge integers represented by linked...

创建于：2025年6月23日

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问题

You're given 2 huge integers represented by linked lists. Each linked list element is a number from 0 to 9999 that represents a number with exactly 4 digits. The represented number might have leading zeros. Your task is to add up these huge integers and return the result in the same format.

Example

For a = [9876, 5432, 1999] and b = [1, 8001], the output should be solution(a, b) = [9876, 5434, 0].

Explanation: 987654321999 + 18001 = 987654340000.

For a = [123, 4, 5] and b = [100, 100, 100], the output should be solution(a, b) = [223, 104, 105].

Explanation: 12300040005 + 10001000100 = 22301040105.

in c++ wihtotu comments

思考

Providing C++ solution

The user is asking for a C++ implementation of adding up two huge integers represented as linked lists or vectors of integers. They want the code without comments. I'll just provide the C++ function that takes two inputs (likely vectors or linked lists) and adds them up. Since explanations and outputs aren't requested, I’ll give the code snippet directly, no extra detail. Here's the function to handle the required operation.

Thought for 9 seconds

回答

cpp
#include <bits/stdc++.h>
using namespace std;

vector<int> solution(const vector<int>& a, const vector<int>& b) {
    int i = static_cast<int>(a.size()) - 1;
    int j = static_cast<int>(b.size()) - 1;
    int carry = 0;
    vector<int> res;

    while (i >= 0 || j >= 0 || carry) {
        int sum = carry;
        if (i >= 0) sum += a[i--];
        if (j >= 0) sum += b[j--];
        res.push_back(sum % 10000);
        carry = sum / 10000;
    }

    reverse(res.begin(), res.end());
    return res;
}

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