Упростите логическое выражение

Simplifying the logical expression step-by-step

Based on the threshold inspection, it's clear that the second term has a bar spanning over B & C, but no bar over A. The expression simplifies to A(B C ∨ \overline{B C} ∨ \bar B), and applying logical identities, it becomes just A. For the second term, it could be A & \bar B & \bar C, but simplifying further leads to the conclusion that the result is A(\bar B + C).

Thought for 1m 3s