#include <bits/stdc++.h> using namespace std; #def...

Tạo vào: 23 tháng 3, 2025

Trả lời bằng O3 Mini High bởi Chat01

Câu hỏi

#include <bits/stdc++.h>
using namespace std;
#define int long long

set<vector<int>> st,st2;

void pre(int lm){
for(int i=0;i<=lm;i++){
for(int j=0;j<=lm;j++){
st.insert({3i+3j+2,3i+1,3j+1});
st.insert({3i+3j+3,3i+1,3j+2});
st.insert({3i+3j+3,3i+2,3j+1});
st.insert({3i+3j+6,3i+2,3j+2});
}
}

text
for(int i=0;i<=lm;i++){ for(int j=0;j<=lm;j++){ st2.insert({3*i+3*j+2,3*i+1,3*j+1}); } }

}
void solve(){
int n; cin >> n;

text
int lm = sqrt(2*n); pre(lm); vector<int> t(n); for(auto &p:t){ cin >> p; if(p == 1){ auto it = *st.begin(); st.erase(it); st2.erase(it); cout << it[1] << " " << it[2] << endl; } else{ auto it = *st2.begin(); st.erase(it); st2.erase(it); cout << it[1] << " " << it[2] << endl; } }

}

int32_t main() {

text
int t; cin >> t; while(t--){ solve(); }

}
This is the correct c++ code
But my java code is giving wrong answer
import java.io.;
import java.util.
;

public class Mainn {
static class FastReader {
BufferedReader br;
StringTokenizer st;

text
public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } } public static List<Integer> primefactor(int n){ List<Integer> arr=new ArrayList<>(); for(int i=2;i*i<=n;i++){ while(n%i==0){ arr.add(i); n/=i; } } if(n>1) arr.add(n); return arr; } public static void main(String[] args) { FastReader sc = new FastReader(); int tc = sc.nextInt(); StringBuilder sb = new StringBuilder(); ArrayList<int[]> arr=new ArrayList<>(); ArrayList<int[]> brr=new ArrayList<>(); for(int i=0;i<=350;i++){ for(int j=0;j<=350;j++){ arr.add(new int[]{3*i+3*j+2,3*i+1,3*j+1}); arr.add(new int[]{3*i+3*j+3,3*i+1,3*j+2}); arr.add(new int[]{3*i+3*j+3,3*i+2,3*j+1}); arr.add(new int[]{3*i+3*j+6,3*i+2,3*j+2}); } } for(int i=0;i<=350;i++){ for(int j=0;j<=350;j++){ brr.add(new int[]{3*i+3*j+2,3*i+1,3*j+1}); } } Collections.sort(arr,(x,y)->(x[0]==y[0])?(x[1]-y[1]):(x[0]-y[0])); Collections.sort(brr,(x,y)->(x[0]==y[0])?(x[1]-y[1]):(x[0]-y[0])); //for(int it[]:brr) System.out.println(Arrays.toString(it)); label: while (tc-- > 0) { int n=sc.nextInt(); int a[]=new int[n]; for(int i=0;i<n;i++) a[i]=sc.nextInt(); int x=0,y=0; for(int it:a){ if(it==1){ System.out.println(arr.get(x)[1]+" "+arr.get(x)[2]); if(brr.get(y)[1]==arr.get(x)[1] && brr.get(y)[2]==arr.get(x)[2]) y++; x++; } else{ System.out.println(brr.get(y)[1]+" "+brr.get(y)[2]); if(brr.get(y)[1]==arr.get(x)[1] && brr.get(y)[2]==arr.get(x)[2]) x++; y++; } } } System.out.print(sb); }

}

Suy nghĩ

Evaluating the strategy

I'm working through the user's code request, which includes <bits/stdc++.h>, using namespace std;, and #define int long long. This setup typically supports frequent programming competitions, providing essential libraries and optimizing integer handling.

Delving into specifics

I'm examining the request for a function to generate all possible strings from a list of strings, focusing on the requirements and constraints outlined, such as ensuring the strings are unique.

Focusing on the objective

I’m noting the task to generate all possible strings from a list of strings, ensuring the generated strings are unique and reflect the original list.

Handling string combinations

I’m curious about managing all possible strings from a list of strings, ensuring each string is unique and representative of the original list, using efficient data structures and algorithms.

Piecing together a solution

I’m delineating the choice of generating all unique strings from a list, optimizing for memory usage, and ensuring each string is both derived from and representative of the original list.

Formulating a method

I'm considering a function to generate all unique strings from a list of strings, while optimizing for memory and ensuring each string is derived and reflects the original list.

Reasoned for 7 seconds

Trả lời

It seems like your Java code is performing similar logic to the C++ code but with some differences in how data is handled. Let me go over a few potential issues and suggestions for improvement.

Key Issues:

  1. Sorting arrays arr and brr:
    • In the C++ code, st and st2 are sets that maintain the order of insertion and also guarantee uniqueness. In Java, you are using ArrayList<int[]> and sorting them based on the first element (x[0]). However, the logic in C++ doesn't involve sorting st and st2; they are just sets, and the order of traversal depends on the set's internal structure.
    • Potential Issue: By sorting the arrays in Java, you may not be simulating the exact behavior of the C++ code, which relies on the natural ordering of sets (likely in increasing order). Instead, by sorting, you might cause the mismatch between the two versions.
  2. Index Handling (x and y):
    • Your variables x and y are intended to track the position in arr and brr, respectively. However, the logic for determining whether to increment x or y based on matching values is flawed in your Java code.
    • Specifically, the condition if(brr.get(y)[1]==arr.get(x)[1] && brr.get(y)[2]==arr.get(x)[2]) y++ might not reflect the exact logic intended by the C++ code.

Suggested Changes:

  1. Avoid Sorting:
    • Instead of sorting arr and brr, you should treat them as LinkedHashSet in Java to preserve the order of insertion, just like C++ sets do.
  2. Fix the Index Logic:
    • The logic for when to increment x and y should be adjusted to match the behavior from C++. Essentially, you should only increment x or y when you are sure that the right set has been processed.

Improved Java Code:

Here is an updated version of your Java code with the necessary fixes:

java
import java.io.*; import java.util.*; public class Mainn { static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } } public static void main(String[] args) { FastReader sc = new FastReader(); int tc = sc.nextInt(); StringBuilder sb = new StringBuilder(); // Initialize the sets directly instead of sorting. Set<List<Integer>> st = new LinkedHashSet<>(); Set<List<Integer>> st2 = new LinkedHashSet<>(); for (int i = 0; i <= 350; i++) { for (int j = 0; j <= 350; j++) { st.add(Arrays.asList(3 * i + 3 * j + 2, 3 * i + 1, 3 * j + 1)); st.add(Arrays.asList(3 * i + 3 * j + 3, 3 * i + 1, 3 * j + 2)); st.add(Arrays.asList(3 * i + 3 * j + 3, 3 * i + 2, 3 * j + 1)); st.add(Arrays.asList(3 * i + 3 * j + 6, 3 * i + 2, 3 * j + 2)); } } for (int i = 0; i <= 350; i++) { for (int j = 0; j <= 350; j++) { st2.add(Arrays.asList(3 * i + 3 * j + 2, 3 * i + 1, 3 * j + 1)); } } label: while (tc-- > 0) { int n = sc.nextInt(); int[] a = new int[n]; for (int i = 0; i < n; i++) a[i] = sc.nextInt(); // Process each query for (int it : a) { if (it == 1) { // Take from st List<Integer> curr = st.iterator().next(); // Get the first element st.remove(curr); st2.remove(curr); sb.append(curr.get(1)).append(" ").append(curr.get(2)).append("\n"); } else { // Take from st2 List<Integer> curr = st2.iterator().next(); // Get the first element st.remove(curr); st2.remove(curr); sb.append(curr.get(1)).append(" ").append(curr.get(2)).append("\n"); } } } System.out.print(sb.toString()); } }

Key Changes:

  1. Replaced Sorting with LinkedHashSet:

    • I used LinkedHashSet instead of sorting the arrays to maintain insertion order.
  2. Simplified Logic for Element Removal:

    • For both st and st2, I directly get the first element using iterator().next(), and then remove it from both sets.
  3. Output Handling:

    • I used StringBuilder to append the output for efficiency, and at the end, the result is printed.

Performance Consideration:

The LinkedHashSet is used to maintain the insertion order, and the set operations are generally O(1), so the performance should be in line with the original C++ code.

This approach should now match the behavior of the C++ code more closely and give the correct answer.

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