已知过点 A(−1,0) 、 B(1,0) 两点的动抛物线的准线始终与圆 x2+y2=9 相切,该抛物线焦点 P 的轨迹是某圆锥曲线 E 的一部分。<br>(1) 求曲线 E 的标准方程;<br>(2) 已知点 C(−3,0) , D(2,0) ,过点 D 的动直线与曲线 E 相交于 M 、 N ,设 △CMN 的外心为 Q , O 为坐标原点,问:直线 OQ 与直线 MN 的斜率之积是否为定值,如果为定值,求出该定值;如果不是定值,则说明理由。
Suy nghĩ
Solving parabola problem
I need to solve this in Chinese, focusing on a parabola with fixed focal chord AB, where A(-1,0) and B(1,0), and the directrix is tangent to the circle x^2 + y^2 = 9. The focus P moves, and I'm asked to find the equation of curve E formed by the set of all such foci. The directrix is tangent to the circle, and I need to find the relationship between the coordinates of the focus. The focus's position involves using the definition of a parabola: the distance to the focus equals the distance to the directrix.
Considering distances and focus
We have two fixed points A(-1,0) and B(1,0) on the parabola. For a point P (the focus) and a directrix L, the distance from A to P equals the distance from A to L, and similarly for B. I’m thinking of using the equidistant property of parabolas and the relationship between focus and directrix to determine how A and B connect to the focus. The directrix L is tangent to the circle x^2 + y^2 = 9, and we know that this distance is 3. This can help solve the problem.
Deriving focus and directrix relations
I’m working through relationships involving the focus and directrix of the parabola. For A(-1,0) and B(1,0), the distance from A and B to the directrix involves calculating absolute values based on the equation of the line. When we subtract these distances, I find a relation between the coefficients a and the focus p. After some more steps, it seems the focus lies on the y-axis due to the symmetry of A and B. Contradictions suggest corrections, and I suspect the focus is at (0, q), but the actual solution depends on testing specific cases.
Locus of the focus
I'm finding the locus of the focus for the parabola with directrices at y = 3 or y = -3, and passing through A(-1, 0) and B(1, 0). After some calculations, I derive that the locus of foci satisfies the ellipse equation 9x2+8y2=1. The focus points lie on this ellipse, with p2+q2 between 8 and 9. So, the answer is an ellipse, and I confirm the equation matches the necessary conditions.
Finding circumcenter Q
I'm exploring how to calculate the circumcenter Q for triangle CMN, where points M and N are on the intersection of the ellipse and a line. I want to find the relationship between the coordinates of Q, the midpoint of M and N, and the fixed point C. To do this, I use the fact that Q is equidistant from C and any M or N. I’m trying to eliminate unnecessary variables, and I'm also considering using certain geometrical properties like the radical axis to simplify the process.
None
Reasoned for 1m 17s
Trả lời
下面给出一种答案思路,最终结果为
焦点的轨迹 E 的标准方程为
9x2+8y2=1.
对于点 C(−3,0) 和 D(2,0)以及任一过 D 的直线(设斜率为 k)与 E 的交点 M,N构成的三角形 CMN,其外心 Q 与原点 O 所连直线的斜率与直线 MN 的斜率的乘积恒等于