問題

使用12,12,11,3这4个数字如何通过加减乘除和括号计算24点?每个数字只能使用一次且必须使用一次,但不用保持数字的顺序,给出所有可能的计算方法。你是一个数学天才,解24点的老手,加油!

思考

Wondering about calculations

I’m tasked with computing 24 using 12, 12, 11, and 3. Operations include addition, subtraction, multiplication, and division. Each number must be used only once.

Identifying strategies

I’m mapping out the task of finding expressions that yield 24 using the numbers 12, 12, 11, and 3 with basic operations. Considering permutations and different combinations of these numbers and operators to generate expressions.

Piecing together new ways

I'm mapping out expressions to get 24 using 12, 11, and 3. None of these ideas worked, but I'm trying another angle.

Trying different ways

I explored various combinations of arithmetic operations to obtain a result close to 24. Each attempt was carefully calculated, but none achieved the target value of 24.

Assessing possibilities

I’m working through different combinations of the given numbers, trying various arithmetic operations to generate new values and identify possible solutions. Each attempt involves a mix of addition, subtraction, multiplication, and division, leading to a range of potential outcomes.

Testing combinations

I’m experimenting with various arithmetic operations on the numbers 12, 11, and 3 to see if any combination results in 24. Despite extensive calculations, none have been successful.

Evaluating arithmetic expressions

I tested various arithmetic expressions involving the numbers 12, 12, 11, and 3, including addition, subtraction, multiplication, and division, to compare their results.

Evaluating expressions

Interestingly enough, I’m working through different mathematical expressions to determine if any equal 51. Each calculation is unique, and I’m gathering possibilities to reach the target sum.

Evaluating expressions

I'm noting different combinations of operations, including addition, subtraction, multiplication, and division, to determine their outcomes. Each expression is carefully calculated, considering the precedence of operations.

Adjusting strategies

OK, let's think through different combinations of numbers and operations, ensuring each calculation's precedence is clear, and I'm interested in finding the most effective solution.

Evaluating possibilities

I worked through various calculations and algebraic manipulations to find the value of 12 * (11 -12 +3). Interestingly, I found multiple ways to achieve the same result: 24.

Examining alternatives

I'm considering various arithmetic and multiplication combinations involving 12, 11, and 3 to find a distinct and correct solution.

Evaluating calculations

I’m working through various arithmetic expressions, including multiplication, division, and addition, to find a specific value. Progress is evident as I test different combinations to ensure accurate results.

Assessing problem-solving methods

I evaluated a series of mathematical rearrangements. Each confirmed: (12×(3+(1112)))=24(12 \times (3 + (11 -12))) = 24, consistent with previous patterns observed.

Assessing options

I’m working through various combinations by substituting and simplifying parts of the equations, aiming to find a unique solution.

Identifying unique approaches

OK, let's see. The solutions are various rearrangements of the same calculation, leading to finding all unique ways to express 24.

Examining various methods

I explored nine different mathematical methods for calculating 12×212 \times 2. Each method provided unique insights, leading me to the consistent final results of 24 and 168.

Aligning methods

I’m revisiting methods 1 through 8 to ensure all expressions for 24 are included, presenting each step clearly.

Mapping out expression options

I’m focusing on different ways to combine and simplify the numbers 12, 11, 3, and 8 to achieve 24. After trying various combinations including addition, subtraction, multiplication, and division, I conclude that the expression 12×(1112+3)12 \times (11 -12 +3) uniquely yields 24.

回答

要用数字12、12、11、3通过加减乘除和括号计算出24点,每个数字只能使用一次且必须使用一次。以下是所有可能的计算方法:

方法一: 12×(1112+3)=12×2=2412 \times (11 - 12 + 3) = 12 \times 2 = 24

方法二: 12×(11(123))=12×2=2412 \times (11 - (12 - 3)) = 12 \times 2 = 24

方法三: 12×(3+(1112))=12×2=2412 \times (3 + (11 - 12)) = 12 \times 2 = 24

方法四: 12×(3(1211))=12×2=2412 \times (3 - (12 - 11)) = 12 \times 2 = 24

方法五: 12×((3+11)12)=12×2=2412 \times ((3 + 11) - 12) = 12 \times 2 = 24

方法六: 12×(11+(312))=12×2=2412 \times (11 + (3 - 12)) = 12 \times 2 = 24

方法七: 12×((11+3)12)=12×2=2412 \times ((11 + 3) - 12) = 12 \times 2 = 24

以上方法都是通过巧妙地重组数字和运算符,实现了计算24点的目标。

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