设 S = {1,2,3,..., n}, 令 f(S) 表示所有 S 的非空子集和的平方和, 即:...

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질문

设 S = {1,2,3,..., n}, 令 f(S) 表示所有 S 的非空子集和的平方和, 即:

f(S)=TS,T(xTx)2f(S) = \sum_{T \subseteq S, T \neq \emptyset} (\sum_{x \in T} x)^2

求当 n = 2023 时, f(S) mod (10^9 + 7) 的值。

답변

Summing squares of subset sums

OK, let's think this through: we're calculating the sum of squares of sums for all non-empty subsets of a set SS, and then take it modulo 109+710^9 + 7.

Breaking it down

I’m working through the identity for f(S)f(S) by expanding and separating sums, examining each xx in TT, and considering all non-empty subsets TT.

Confirming subset contributions

I’m verifying that each element xx in SS appears in exactly 2n12^{n-1} non-empty subsets, ensuring the sum of x2x^2 across all TT accurately reflects these contributions.

Summing pairs

I’m gathering info on the sum of products xx and yy over all non-empty subsets TT, considering how each distinct pair appears in 2n22^{n-2} subsets.

Summing distinct pairs

I’m adding up the products of all distinct pairs xx and yy from {1,,n}\{1, \ldots, n\}, ensuring each pair is counted only once in the sum.

Crafting the formula

I’m working on simplifying f(S)f(S) by unifying the sums of squares for each xx in SS with the sum of products for distinct pairs (x,y)(x, y), leading to a concise expression.

Breaking down the approach

I’m simplifying the expression by noting that the sum of squares plus the sum of products for distinct pairs is half the sum of the squares plus the square of the sum of xx.

Combining and simplifying

I’m amalgamating terms, isolating common factors, and streamlining the algebraic expression to deduce a simpler closed-form solution for f(S)f(S).

Finalizing the expression

I’m adding the final touches to a simplified version of f(S)f(S), factoring 3n2+7n+23n^2+7n+2 into (3n+1)(n+2)(3n+1)(n+2), and ensuring all terms are neatly combined for a clearer form.

Finalizing the steps

I’m mapping out the calculation for f(S)f(S) modulo 109+710^9 + 7 by carefully breaking down the terms, ensuring each part is accurately computed and combined to find the final result.

Isolating powers

I’m piecing together the factorization of large numbers to simplify f(S)f(S) modulo 109+710^9 + 7, isolating common factors and simplifying the division by 12.

Breaking down calculations

I’m meticulously assembling the factorization of large numbers to streamline f(S)f(S) modulo 109+710^9 + 7, isolating common factors, and making the division by 12 easier.

Calculating powers

I’m multiplying prime factors of large numbers to simplify f(S)f(S) modulo 109+710^9 + 7, accumulating powers of 2, 3, 5, 7, 17, 11, 23, and 607 to streamline the division by 12.

Pulling together

OK, let me see. I’m combining PP divided by 12 with 220212^{2021} to form QQ, then aligning these terms for f(S)f(S) modulo 109+710^9 + 7.

Ensuring precision

I’m moving through the steps to compute f(S)f(S) modulo 109+710^9 + 7, ensuring each term is accurately factored and multiplied, while maintaining the integrity of the factors.

Breaking down the exponentiation

OK, let me see. I’m thinking about a method to compute 220232^{2023} modulo 109+710^9 + 7 by breaking it into smaller parts and using modular exponentiation techniques.

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