解出flag 根据这四个文件

python
from pathlib import Path, PurePosixPath
base = Path('/mnt/data')
for p in base.iterdir():
    print(p, p.stat().st_size)

python
print(Path('/mnt/data/题目描述.txt').read_text(encoding='utf-8'))

python
print(Path('/mnt/data/public.txt').read_text())

python
pub = Path('/mnt/data/public.txt').read_text().splitlines()
len(pub), pub[0][:100], pub[0][-50:], pub[0].count('.')

(3,
 '75b8da92a0a4caf5cc838133cf138aa114d10cdcd05a4664dba48417b3ab64959c7f56dfb5fd05bb8165b069f22466f4c384',
 '7fe082c4db085ca2f71443932e76fe91cb3bf14def5138d223',
 0)

python
len(pub[0])


512

python
ct = Path('/mnt/data/ciphertext.txt').read_text().strip()
len(ct), ct[:100], ct[-50:]


(512,
 '464c1b4adee3731c5372f912385ae67ba74055f282118e8cedbbaedc389d8902d355c9f9fc0abdc5442a15014c167e56b0eb',
 '681a84cc39b6f8449749dc351a2b1e32c20be29ae1699b4fe8')

python
ot_path = Path('/mnt/data/oracle_transcript.txt')
with ot_path.open() as f:
    for i in range(60):
        print(f.readline().rstrip())

python
lines = ot_path.read_text().splitlines()
lines[0:25]


['1 2',
 '1 2',
 '1 3',
 '1 3',
 '1 4',
 '1 4',
 '1 5',
 '1 5',
 '1 5',
 '1 6',
 '1 6',
 '1 7',
 '1 7',
 '1 8',
 '1 8',
 '1 9',
 '1 9',
 '1 a',
 '1 a',
 '1 b',
 '1 b',
 '1 c',
 '1 c',
 '1 d',
 '1 d']

python
import re, itertools
# Check unique first tokens
first_tokens=set()
for line in itertools.islice(lines, 0, 10000):
    if not line.strip(): continue
    first_tokens.add(line.split()[0])
first_tokens, len(lines)


82e40f95f085cd5dc7f9cd70c0503c04ff13e3aae443ae1c3e8aea55211748c0f4ec92fed366e2b8ea8b20e0c7692e4dac957c2e9d09042eaf9ce6214438ab47e47911e32ec41492f6d7afc3b7d5171f8e53fb24d1cc464ed6d1e1889d196e25e9f9a275d31beafcdbc4abcc45bdd45252a7a059f433d8770cae918148226086640d2971c92d37f648d148a78d942a00736a37e373b86bf82',
  '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',
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  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  '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',
  ...},
 1200)

python
from collections import Counter
token_counts = Counter(len(line.split()) for line in lines if line.strip())
token_counts


Counter({2: 1200})

python
weird = [line for line in lines if line.split()[0] not in {'0','1'}][:10]
weird[:5], len(weird)


(['499f9ecade02f71941e68da5346ffe3930a64cbeff7d7636497c16f31696fbd95fbd0f14a7231890b7dfe239c3496f51048b4c8b6a647f750083c921ea37170d186bc6a6fdab7308a93a69420403da5b34726e8a72393492a3d6a0e53a40b2f9cc94eef020b49d3ff70d5ce7fee1eed9a59f287861805770648cc82f0779b652ec900f106a07aad95d6a8a29279ac34b2173e51c3b94659516337d78979884959d3bac747f4f391daedbe304327fe847f2a3d316b62236369b74d01174fb98a570a21eccda86aa34a4dc3b9f39371e70b4e244ac11553d749ae4b3f321af7a0f61e04770972c03b13bfb42ada5d24068bda0ed7707797397dd1c4f6f693ae562 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',
  '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',
  '299642577e49804bbbbc9d9b76bf8c1b9617e0a4555efd16a7812463f03ac54e00bb320b769b2c4befc65000af1a0633b38d9bdc2d027813b24e6884ed49ff0bc42cf23f55dade61232b96a37f5eedc6c3504b893f98766beade4421d1a19dad248fbce3e9b491453c3abfdf13db81bf04ac0e21467ce016d681bde5f0cd935a95f0ad67598a4a70801649c7f9a0da9358809a60fb14debfe6785c40a4d9ef11e47bc52b300fbc1bd5d953ecdf26107e01197556a880b038b9d05189e953f1e62039309a90717deaa10098693a53d9b8bb388c5e02786cd0d1d81befee07cdfdab21994a2d30371a5195d6bfe382039b658cc95709355493eba9395582a654f7 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',
  '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 152ac32277a2331a05b05274efd554160221a2130c3d9a66145a469b45cd13e847cae58cfe824e30c7b90ef69fa4ab1bb7014a5388a433ab6094f94d3ef916f6a9c8d458bd1f48f176c2dc877042f9bbf6cd8404064ce860dd271886d7e5d559ab8c50aca6ccbe597df44bd919f052efbfaa8c296c856adf51c3a57a1e9dea90a7e51b7dc60de05e8f81ead66b9b15dc4893651a564a32c7a96b7d4192fb44f69ab1bc33457897313d864388086023f3f62e8f8d63ca68ebaffe6f35111f1ecad52d72e1c1af68be2aac88066fc371d2439ca37b7d586c00849a40eae4d69c91af4ed9cca03a19ac7e50b7cdd732214db0bb1171edac59f9e0304d9d530ea43d',
  '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'],
 10)

python
w0 = [line for line in lines if line.split()[0] not in {'0','1'}][0]
t1,t2 = w0.split()
len(t1), len(t2), t1[:20], t2[:20]


(512, 512, '499f9ecade02f71941e6', '3bfdc969f15872587c7f')

python
idx_first_not1 = next(i for i,l in enumerate(lines) if l.split()[0] != '1')
idx_first_not1, lines[idx_first_not1-3:idx_first_not1+3]


(80,
 ['1 27',
  '1 27',
  '1 28',
  '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',
  '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',
  '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'])

python
for i in range(70, 90):
    l=lines[i]
    a,b=l.split()
    print(i, len(a), len(b), a[:8], b[:8])

python
resp_candidates = [line for line in lines if line.split()[1] in {'0','1'}]
len(resp_candidates), resp_candidates[:10]


(0, [])

python
zero_lines=[line for line in lines if line.split()[0]=='0']
len(zero_lines), zero_lines[:5]


(0, [])

python
from collections import defaultdict
lens=Counter(len(line.split()[0]) for line in lines)
lens


Counter({512: 980, 511: 131, 1: 80, 510: 9})

python
import math, random
N=int(pub[0],16)
e=int(pub[1])
# find a few lines where both tokens length about 512 and test relation
pairs=[]
for line in lines[80:90]:
    a,b=line.split()
    pairs.append((int(a,16), int(b,16)))
tests=[]
for a,b in pairs:
    tests.append(pow(a,e,N)==b)
tests


[False, False, False, False, False, False, False, False, False, False]

python
import sympy as sp
ratios=[]
for a,b in pairs:
    ratios.append((b*sp.mod_inverse(a,N))%N)
len(set(ratios)), ratios[:3]


(10,
 [4857567784555452763449492775226342516750080075050252781213791982638876706132568085949159368923259758635847334965665272277316317155864404508337192069214632727314478471039117414219782140091404771044640842361609990058457058464251564506559152745515542167034811825575642672473804806727872823160606717237836925639993945668759058838871856548194134995061501796538837307220529770496090477011980935095314804392475058196337408176484023688174879392002163796629020804671862861337887325398253349124345982429614786077093038461398576918898169255771053615047143411283712218482445125892421170190146558763868310821533914902396826942625,
  8225131433230449924050957418509240954720574764894161845916292288677811506613721956773133621835033831785126119742713943321781499471072377561870848096043175725498122101021218744850252000285597624967593711131021741268174110212431667599618132240733152364010699866013351306899896458072814179312145420101381178093996832170979594401168667710375109895025308360446534690421337448396805431126541040163118857198952504192308437451396100503942993664115871571506066407623709495907777427283157266505118889485972698406712939117353182495711431928942247211578593866177030699240457147240303913680654623498829410724554754616934926455379,
  8557848953866602681055083553983880792954617207136609830270527068650560754805683419332977876994721609322882950503564053219676500656870199090319914465368846939067846627824497779088322767416574827143376516085033961749605961293754382572096761515038688191284230211855492442012749290537196837650272992912381227873325061586176907433337700098120003521839405524351559834789775814383243947307936893052800089354466008638035211505764763639143234108951297585153956460241056967333743023927451347784599250475090253422610902155270943983202617666087671127342999665813750799744850433831858818865212488445426660614192746255748759235451])

python
diffs=[(b-a)%N for a,b in pairs]
len(set(diffs)), diffs[:3]


(10,
 [13140135444385232223857021693402248549069545455566090862512576746124027065505597110397140297948074277274596526525901793294423504879108507445989721727221407543204647490620713013857130969142125718148593551891442473891710774375270026042347208447834756215579343142087280522498294396630855514603607528236830705472137381262773759008347957517594571464003307803226354929894038924385780379531928562585449721732327082623605801046468568814811338075663235640011220800541348633041993853309280099738174529387417801349623894777592613192883567342729041096116978216269587551897489870074824180377463435365652426775698438590146016613744,
  2868460393760678974823790454432770558833672411308564506701087638643163156526102081925394769610475217521891020584958381854597103232962449934779867011018561404350214785359633890387940904694908972606033091668983735553830300246558207116521558582252908115719367835077975579616755193733579996156660108724334335868872653124589247831927722975073907313140227243970159320558778674608840657751773474104687862652929788718519506794721460735968868974570468563352676468846780097818209444581446996961239576809261936895283103972451652366525869117323055656765162610101275739005297936719538992202889949206098453904494829392831722102390,
  3734565487876618255649281728780173131507650025481446567367779774998763891304668194416029254558392493359228138502892996817138058726668996995158616231667071026382605246865797647638671287352118161498116373902143604111890376557843160121032238976745889364028882081387164067012181377922493564404857302546925877666026497363689777314066702735648739575608161542958840020837596821050811546624710413768264314471236148469830848857277233805883657824395018545909602751533154568505418358308277765523872574128197741594770264841400190553785067609242808942464332604906620434356158194116916669370168639765656713501844721654257525808606])

python
tests=[]
for line in lines[80:90]:
    c_hex,m_hex = line.split()
    c=int(c_hex,16); m=int(m_hex,16)
    tests.append(pow(m,e,N)==c)
tests


[False, False, False, False, False, False, False, False, False, False]

python
import math
pairs=[]
for line in lines:
    a,b=line.split()
    # interpret a and b as hex integers
    m=int(a,16) if all(ch in '0123456789abcdef' for ch in a.lower()) else int(a)
    c=int(b,16)
    pairs.append((m,c))
# compute gcd for first 200 pairs
gcds=[]
for m,c in pairs[:200]:
    diff=(pow(m,e,N)-c)%N
    g=math.gcd(diff,N)
    gcds.append(g)
set([g for g in gcds if g!=1 and g!=N]) , gcds[:10]


(set(), [1, 1, 1, 1, 1, 1, 1, 1, 1, 1])

python
g_non=[]
for m,c in pairs[:500]:
    diff=pow(m,e)-c
    g=math.gcd(diff,N)
    if g!=1 and g!=N:
        g_non.append(g)
len(g_non), g_non[:3]

python
import numpy as np, math
# sample 20 pairs from big part
big_pairs=[]
for line in lines[80:120]:
    a,b=line.split()
    big_pairs.append((int(a,16), int(b,16)))
diff_bits=[(a^b).bit_length() for a,b in big_pairs]  # not diff but XOR
# Compute approximate hamming? can't
min(diff_bits), max(diff_bits), diff_bits[:5]


(2038, 2047, [2047, 2047, 2047, 2047, 2047])

python
abs_bits=[abs(a-b).bit_length() for a,b in big_pairs]
min(abs_bits), max(abs_bits), abs_bits[:5]


(2037, 2047, [2044, 2047, 2045, 2046, 2047])

python
tests=[]
for a,b in big_pairs[:20]:
    tests.append(pow(b,e,N)==a)
sum(tests), tests[:10]


(0, [False, False, False, False, False, False, False, False, False, False])

python
for i in range(len(lines)-5, len(lines)):
    a,b=lines[i].split()
    print(i, len(a), len(b), a[:10], b[:10])

python
last_line=lines[-1]
c_hex, m_hex = last_line.split()
m_bytes=bytes.fromhex(m_hex)
m_bytes[:20], len(m_bytes), m_bytes


(b'flag{7a94faqe-e0a3-1',
 66,
 b'flag{7a94faqe-e0a3-1qf0-8527-30050575612d-983f85d9-e0a3-11f0-88cc\xbe')

python
ciphertext_hex = Path('/mnt/data/ciphertext.txt').read_text().strip()
# find lines where either token equals ciphertext_hex
matches=[(i,l) for i,l in enumerate(lines) if ciphertext_hex in l.split()]
len(matches), matches[:3], matches[-3:]


(1,
 [(1199,
   '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 666c61677b37613934666171652d653061332d317166302d383532372d3330303530353735363132642d39383366383564392d653061332d313166302d38386363be')],
 [(1199,
   '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 666c61677b37613934666171652d653061332d317166302d383532372d3330303530353735363132642d39383366383564392d653061332d313166302d38386363be')])

python
inside="7a94faqe-e0a3-1qf0-8527-30050575612d-983f85d9-e0a3-11f0-88cc"
parts=inside.split('-')
parts, list(map(len,parts)), sum(len(p) for p in parts)+len(parts)-1


(['7a94faqe',
  'e0a3',
  '1qf0',
  '8527',
  '30050575612d',
  '983f85d9',
  'e0a3',
  '11f0',
  '88cc'],
 [8, 4, 4, 4, 12, 8, 4, 4, 4],
 60)

python
pattern="666c61677b"
hits=[]
for i,l in enumerate(lines):
    if pattern in l:
        hits.append(i)
hits[:10], len(hits)


([1199], 1)

python
import math, time
# Parse transcript pairs as (c, m_noisy) or (m_noisy, c)? Determine from last line: first is ciphertext, second is plaintext (smaller len 132), so yes.
pairs_cm=[]
for line in lines:
    c_hex, m_hex = line.split()
    c=int(c_hex,16)
    m=int(m_hex,16)
    pairs_cm.append((c,m))
start=time.time()
factors=set()
vals=[]
for i,(c,m) in enumerate(pairs_cm):
    # compute pow(m,e,N) - c mod N
    diff=(pow(m,e,N)-c) % N
    g=math.gcd(diff,N)
    if 1<g<N:
        factors.add(g)
        vals.append((i,g))
end=time.time()
len(factors), list(factors)[:3], vals[:5], end-start


(0, [], [], 0.39893579483032227)

python
factors=set()
vals=[]
for i,(m,s) in enumerate(pairs_cm): # but pairs_cm uses int(c,m). reuse variable names
    m_val=m # actually c stored
    s_val=s # m stored
    diff=(pow(s_val,e,N)-m_val) % N
    g=math.gcd(diff,N)
    if 1<g<N:
        factors.add(g)
        vals.append((i,g))
len(factors), vals[:5]


(0, [])

python
from collections import Counter, defaultdict
c_counts=Counter(c for c,_ in pairs_cm)
# how many ciphertexts repeated?
repeated=[(c,count) for c,count in c_counts.items() if count>1]
len(repeated), repeated[:10]


(1, [(1, 80)])

python
# collect outputs for ciphertext=1
outs=[m for c,m in pairs_cm if c==1]
len(outs), outs[:5]


(80, [2, 2, 3, 3, 4])

python
import math
g_list=[]
for m in outs:
    g=math.gcd(m-1,N)
    if g!=1 and g!=N:
        g_list.append(g)
len(g_list), g_list[:5]


(0, [])

python
bit_lengths=[m.bit_length() for m in outs]
Counter(bit_lengths).most_common(10), min(bit_lengths), max(bit_lengths)


([(5, 30),
  (4, 16),
  (6, 13),
  (3, 9),
  (2, 4),
  (2047, 4),
  (2046, 2),
  (2044, 1),
  (2041, 1)],
 2,
 2047)

python
import itertools, math
outs_unique=list(set(outs))
# compute gcd of differences with N
factors=set()
for i in range(len(outs_unique)):
    for j in range(i+1, len(outs_unique)):
        d=abs(outs_unique[i]-outs_unique[j])
        g=math.gcd(d,N)
        if 1<g<N:
            factors.add(g)
            break
    if factors:
        break
factors


set()

python
def hamming(a,b):
    return bin(a^b).count("1")
for ch in ['1','9','a','b','c','d','e','f','0','8']:
    print(ch, hamming(ord(ch), ord('q')))

python
hamming(0x7d,0xbe)


4

python
obs = m_bytes.decode('latin1')  # keep bytes mapping 0-255
obs


'flag{7a94faqe-e0a3-1qf0-8527-30050575612d-983f85d9-e0a3-11f0-88cc¾'

python
candidate = obs[:-1].replace('q','1') + '}'
candidate, len(candidate)


('flag{7a94fa1e-e0a3-11f0-8527-30050575612d-983f85d9-e0a3-11f0-88cc}', 66)

python
candidate2 = obs[:-1].replace('q','a') + '}'
candidate2


'flag{7a94faae-e0a3-1af0-8527-30050575612d-983f85d9-e0a3-11f0-88cc}'

python
def xor_repeat(data, key):
    out=bytes([b ^ key[i%len(key)] for i,b in enumerate(data)])
    return out
xored = xor_repeat(m_bytes, mask)
xored[:20], xored.decode('utf-8', errors='replace')


(b'\xf5.\xc1;<q+\x04\xfb!\xd5^\xf6o\xc5l&ug\x0c',
 "�.�;<q+\x04�!�^�o�l&ug\x0c�!�\x02�w�kjuz\r�w�\x18�t�n#ks\x05�!�\x1a�{�9w'y\x10�v�\x1f�z�?$�")

python
# show last line exact
print(last_line[:120])
print(last_line[-120:])

python
c_hex, m_hex = last_line.split()
m_hex[:20], m_hex[:40], len(m_hex)


('666c61677b3761393466', '666c61677b37613934666171652d653061332d31', 132)

python
desc=Path('/mnt/data/题目描述.txt').read_text(encoding='utf-8', errors='ignore')
desc[:500], len(desc)


('双参数噪声', 5)

python
s="读取ciphertext与public的N,e，匹配oracle记录取明文，转ASCII并修正噪声得到flag。"
len(s)


56

python
s="读取密文和公钥N,e，对照oracle输出定位明文，转ASCII并修噪恢复flag。"
len(s)


42

python
s="从文件取密文和公钥N,e，对照oracle输出定位明文，转ASCII并修噪恢复flag。"
len(s)


44

python
s="从文件取密文和公钥N,e，再对照oracle输出定位明文，转ASCII并修噪恢复flag。"
len(s)


45

python
s="从文件取密文和公钥N,e，再对照oracle输出定位明文，转ASCII并修噪恢复flag即可。"
len(s)


47

python
s="从文件取密文和公钥N,e，再对照oracle输出定位明文，转ASCII并修噪恢复完整flag即可。"
len(s)


49

python
s="从文件取密文和公钥N,e，再对照oracle输出定位明文，转ASCII并修噪恢复完整flag即可呀。"
len(s)


50