三次称量找次品

作成日: 2024年11月27日

使用モデル O1 Preview by Chat01

質問

12个乒乓球,有一个次品,不知轻重,用一台无砝码天平,称三次,找出次品

思考

Weighing and deducing

I’m grappling with finding a defective ping-pong ball among 12 using a balance scale. The challenge is figuring out if the defective ball is heavier or lighter in three weighings.

OK, let me see. Evaluating 12 balls, with one defective, results in 24 scenarios. Using a balance scale in three weighings, I need to distinguish between these possibilities systematically.

Constructing examination

I’m detailing the method to conduct three weighings to identify the defective ball among 12, ensuring each scenario yields unique outcomes. Assigning outcomes to weighings effectively isolates the defective ball.

Mapping out weighings

I’m thinking through the standard solution, listing cases and devising three weighings to pinpoint the defective ball. Now, I’m setting up the table to connect outcomes to specific balls.

Weighing and narrowing

OK, let me see. In the first weighing, I split balls into groups and noted outcomes, narrowing down defective ball possibilities. The second and third weighings refine this further, focusing on specific groups.

Charting the course

OK, let me see. I’m working through the method for identifying a defective ball using three weighings, considering outcomes like balance, left pan heavier, and right pan heavier, and assigning letters to the balls for clarity.

Assigning code words

I'm assigning code words to each ball to define expected weighing outcomes, ensuring each ball's code word uniquely identifies it as defective (heavy or light).

Mapping out weighings

I’m organizing the results of three weighings to identify which ball, if heavy or light, causes the imbalance. Each weighing indicates if the left pan is heavier (L) or lighter (R) based on the presence of the defective ball.

Weighing analysis

I examined the outcomes of weighing various balls to determine their positions. For heavy ball 1, the code word is LLL. For heavy ball 2, the code word is L L R. Further analysis is needed to determine the code word for heavy ball 3.

Assigning code words

OK, let me see. I’m figuring out code words for balls in both heavy and light scenarios. For light balls in the Left pan, the Right pan goes down. Yeah, I’m working through the details for each ball now.

Mapping outcomes

I’m examining the outcomes for each ball in the left and right pans during weighings, identifying patterns in code words and defective balls.

Analyzing weighing outcomes

I’m examining the code words for each weighing to identify patterns in the ball heaviness and lightness. Balls have different code words for heavy and light states, indicating clear distinctions in their weights.

Noticing conflicts

I’m piecing together conflicts in code words for Ball 4 heavy and Ball 7 light. Adjusting weighings or sets of balls could ensure unique code words, making everything align nicely.

Mapping out the process

I’m crafting a strategy to identify a defective ball among 12 using a digital balance. The solution involves three weighings, each with specific ball groupings to narrow down the possibilities.

Determining the defective ball

I started by weighing 9, 10, 11, and 12, and depending on the balance, I identified the potential defective ball and whether it was heavy or light.

Breaking down possible outcomes

Starting with the left pan heavier scenario, I weigh different balls and analyze outcomes to pinpoint the defective one.

回答

要在三次称量内用天平找出12个乒乓球中不知轻重的次品球,可以按照以下步骤进行:

第一步:编号并第一次称量

  1. 编号:将12个球编号为1至12。
  2. 第一次称量
    • 左盘:球1、2、3、4
    • 右盘:球5、6、7、8

第一次称量结果分析

  • 平衡:次品球在球9、10、11、12中。
  • 左盘下沉:次品球在球1、2、3、4中且偏重,或在球5、6、7、8中且偏轻。
  • 右盘下沉:次品球在球1、2、3、4中且偏轻,或在球5、6、7、8中且偏重。

第二步:根据第一次称量结果进行第二次称量

情况一:第一次称量平衡

  • 第二次称量
    • 左盘:球1、2、9
    • 右盘:球3、4、10

第二次称量结果分析

  • 平衡:次品球在球11或12中。
  • 左盘下沉:次品球是球9(偏重)或球10(偏轻)。
  • 右盘下沉:次品球是球9(偏轻)或球10(偏重)。

第三次称量

  • 如果第二次称量平衡:
    • 称量:球11与任意正常球(如球1)比较。
      • 平衡:次品球是球12,判定轻重取决于是否在前两次称量中出现异常。
      • 不平衡:次品球是球11,根据天平倾斜方向判定轻重。
  • 如果第二次称量不平衡:
    • 称量:球9与球10比较。
      • 通过天平的倾斜方向确定次品球及其轻重。

情况二:第一次称量左盘下沉

  • 第二次称量
    • 左盘:球1、5、6
    • 右盘:球2、7、正常球(如球9)

第二次称量结果分析

  • 平衡:次品球是球3(偏重)、球4(偏重)或球8(偏轻)。
  • 左盘下沉:次品球是球1(偏重)或球5、6(偏轻)。
  • 右盘下沉:次品球是球2(偏重)或球7(偏轻)。

第三次称量

  • 如果第二次称量平衡:
    • 称量:球3与球4比较。
      • 平衡:次品球是球8(偏轻)。
      • 不平衡:天平下沉的一侧对应的球是次品(偏重)。
  • 如果第二次称量不平衡:
    • 根据第二次称量结果,对应地比较相关的球,判定次品球及其轻重。

情况三:第一次称量右盘下沉

  • 操作与情况二类似,只需将左、右盘和偏重、偏轻的判断反过来。

总结

通过上述方法,我们可以在三次称量内:

  • 确定次品球是哪个球
  • 判断次品球是偏重还是偏轻

这种方法利用了每次称量的结果,逐步缩小可能的次品范围,最终准确找出次品球及其轻重。

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