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okay then help me with this.here flags are like KH...

Creato il: 11 gennaio 2026

Risposto usando GPT-5.2 Thinking da Chat01

Domanda

okay then help me with this.here flags are like KHASCTF{..} .

Python

python
data = bytes.fromhex("34 37 3e 2c 3c 2b 39 04 3b 3d 4c 36 37 1e 37 1d 2d 4e 2d 2d 18 3b 1a 29 48 4f 18 39 09 2f 1a 1c 33 4e 32 4e 1d 38 39 2a")
len(data), data[:10]


(40, b'47>,<+9\x04;=')

Python

python
dec = bytes([b ^ 0x7f for b in data])
dec, len(dec), dec.decode('latin1')


(b'KHASCTF{DB3IHaHbR1RRgDeV70gFvPecL1M1bGFU',
 40,
 'KHASCTF{DB3IHaHbR1RRgDeV70gFvPecL1M1bGFU')

Python

python
data41 = bytes.fromhex("34 37 3e 2c 3c 2b 39 04 3b 3d 4c 36 37 1e 37 1d 2d 4e 2d 2d 18 3b 1a 29 48 4f 18 39 09 2f 1a 1c 33 4e 32 4e 1d 38 39 2a 02")
len(data41), bytes([b^0x7f for b in data41]).decode('latin1')


(41, 'KHASCTF{DB3IHaHbR1RRgDeV70gFvPecL1M1bGFU}')

Pensiero

bash -lc printf '%s ' 'KHASCTF{DB3IHaHbR1RRgDeV70gFvPecL1M1bGFU' | /mnt/data/tenet

Thought for 2m 35s

Risposta

I pulled the flag out of the binary.

What’s going on in tenet

  • check_password() decrypts a global encrypted_flag buffer using xor_decrypt()
  • xor_decrypt() just XORs every byte with 0x7f (xor edx, 0x7f)
  • The encrypted bytes live at encrypted_flag (in .data)

When you XOR-decrypt the bytes, you get:

✅ Flag: KHASCTF{DB3IHaHbR1RRgDeV70gFvPecL1M1bGFU}

Note (why the program “password” is missing })

The program decrypts only 0x28 = 40 bytes and then null-terminates, but the encrypted blob actually includes one more byte that decrypts to }. So:

  • Password that makes the binary print “Congratulations”:
    KHASCTF{DB3IHaHbR1RRgDeV70gFvPecL1M1bGFU (no closing brace)

  • Actual CTF flag format:
    KHASCTF{DB3IHaHbR1RRgDeV70gFvPecL1M1bGFU}

If you want, I can also paste the exact 5–6 commands to reproduce this extraction locally (objdump/od + tiny XOR script).

Domanda

What does this sound want to say? Maybe there's a hidden message inside? help me with this one.. this is steganography

Domanda

this is a intellegence problem.. help me to find it

Domanda

What does this sound want to say? Maybe there's a hidden message inside?

Python

python
wav_path="/mnt/data/alice.wav"
with wave.open(wav_path,'rb') as wf:
    nchan=wf.getnchannels()
    sampwidth=wf.getsampwidth()
    fr=wf.getframerate()
    nframes=wf.getnframes()
    comptype=wf.getcomptype()
    compname=wf.getcompname()
    print(nchan,sampwidth,fr,nframes,comptype,compname)
    frames=wf.readframes(nframes)
len(frames), frames[:10]


(477700, b'\x80\x80\x80\x81\x80\x7f~||}')

Python

python
data=np.frombuffer(frames,dtype=np.uint8)
data.shape, data[:20], data.min(), data.max(), data.mean()


((477700,),
 array([128, 128, 128, 129, 128, 127, 126, 124, 124, 125, 127, 130, 132,
        133, 132, 130, 126, 122, 120, 120], dtype=uint8),
 7,
 247,
 127.90085827925476)

Python

python
def bits_to_bytes(bits):
    # bits is iterable of 0/1 length multiple of 8; msb first
    bits=np.array(bits,dtype=np.uint8)
    n=len(bits)//8
    bits=bits[:n*8].reshape(n,8)
    vals=(bits*np.array([128,64,32,16,8,4,2,1],dtype=np.uint8)).sum(axis=1)
    return bytes(vals.tolist())

lsb1 = data & 1
b1 = bits_to_bytes(lsb1)
# Search for readable substring
print(len(b1))
# find flag-like
for pat in [b"KHASCTF", b"CTF{", b"{", b"flag", b"FLAG"]:
    idx=b1.find(pat)
    print(pat, idx)
# show first 200 bytes printable
print(b1[:200])

Python

python
def bits_to_bytes_lsbfirst(bits):
    bits=np.array(bits,dtype=np.uint8)
    n=len(bits)//8
    bits=bits[:n*8].reshape(n,8)
    weights=np.array([1,2,4,8,16,32,64,128],dtype=np.uint8)
    vals=(bits*weights).sum(axis=1)
    return bytes(vals.tolist())
b1r=bits_to_bytes_lsbfirst(lsb1)
for pat in [b"KHASCTF", b"CTF{", b"{", b"flag", b"FLAG", b"-----BEGIN"]:
    print(pat, b1r.find(pat))
print(b1r[:200])

Python

python
def lsb_bits(data, k, within='lsb_to_msb'):
    mask=(1<<k)-1
    vals=data & mask
    bits=np.empty(len(vals)*k, dtype=np.uint8)
    idx=0
    for v in vals:
        if within=='lsb_to_msb':
            for i in range(k):
                bits[idx]= (v>>i)&1
                idx+=1
        else: # msb_to_lsb within k
            for i in range(k-1,-1,-1):
                bits[idx]= (v>>i)&1
                idx+=1
    return bits

def bitstream_to_bytes(bits, byte='msb_first'):
    if byte=='msb_first':
        return bits_to_bytes(bits)
    else:
        return bits_to_bytes_lsbfirst(bits)

def test_k(k):
    out=[]
    for within in ['lsb_to_msb','msb_to_lsb']:
        bits=lsb_bits(data,k,within=within)
        for byteorder in ['msb_first','lsb_first']:
            b=bitstream_to_bytes(bits, byte='msb_first' if byteorder=='msb_first' else 'lsb_first')
            # find interesting patterns
            idx=b.find(b'KHASCTF')
            idx2=b.find(b'-----BEGIN')
            idx3=b.find(b'CTF{')
            score=sum(32<=c<127 for c in b[:200]) # printable in first 200
            out.append((within,byteorder,idx,idx3,idx2,score,b[:60]))
    return out

for k in [1,2,3,4]:
    res=test_k(k)
    print("k",k)
    for r in res:
        within,byteorder,idx,idx3,idx2,score,preview=r
        if idx!=-1 or idx3!=-1 or idx2!=-1 or score>120:
            print(r)

Python

python
import matplotlib.pyplot as plt, numpy as np

Python

python
# create spectrogram
from scipy.signal import spectrogram
f, t, Sxx = spectrogram((data.astype(np.float32)-128)/128.0, fs=fr, nperseg=1024, noverlap=768)
Sxx_db=10*np.log10(Sxx+1e-12)
Sxx_db.shape, f.max(), t.max()


((513, 1863), 5525.0, 43.18407239819005)

Python

python
import matplotlib
matplotlib.use("Agg")
plt.figure(figsize=(12,6))
plt.imshow(Sxx_db, aspect='auto', origin='lower', extent=[t.min(), t.max(), f.min(), f.max()])
plt.ylim(0,5000)
plt.xlabel("Time (s)")
plt.ylabel("Frequency (Hz)")
plt.title("Spectrogram")
out_path="/mnt/data/alice_spectrogram.png"
plt.savefig(out_path, dpi=200, bbox_inches='tight')
plt.close()
out_path


'/mnt/data/alice_spectrogram.png'

Python

python
import matplotlib
matplotlib.use("Agg")
plt.figure(figsize=(12,6))
plt.imshow(Sxx_db, aspect='auto', origin='lower', extent=[t.min(), t.max(), f.min(), f.max()])
plt.ylim(0,5000)
plt.xlabel("Time (s)")
plt.ylabel("Frequency (Hz)")
plt.title("Spectrogram")
out_path="/mnt/data/alice_spectrogram.png"
plt.savefig(out_path, dpi=200, bbox_inches='tight')
plt.close()
out_path


'/mnt/data/alice_spectrogram.png'



<<ImageDisplayed>>

Python

python
import numpy as np
from scipy.signal import butter, filtfilt, hilbert

x = (data.astype(np.float32)-128.0)/128.0
# bandpass 900-1100 Hz
low=900/(fr/2)
high=1100/(fr/2)
b,a=butter(4,[low,high],btype='band')
xf=filtfilt(b,a,x)
env=np.abs(hilbert(xf))
# smooth env
win=int(fr*0.02)  # 20ms window
if win<1: win=1
kernel=np.ones(win)/win
env_s=np.convolve(env,kernel,mode='same')
env_s[:10].mean(), env_s.max()


(0.10370493306539941, 0.9370639146332858)

Python

python
np.percentile(env_s,[5,10,25,50,75,90,95,99])


array([2.58835328e-08, 4.93030725e-08, 1.62752073e-07, 5.00835170e-06,
       4.48823611e-04, 9.00047951e-01, 9.36939567e-01, 9.36948048e-01])

Python

python
thr=0.3
on = env_s > thr
on.mean(), on[:100].sum()


(0.1775675109901612, 11)

Python

python
# get run lengths and state changes
diff=np.diff(on.astype(np.int8))
starts=np.where(diff==1)[0]+1
ends=np.where(diff==-1)[0]+1
if on[0]:
    starts=np.r_[0,starts]
if on[-1]:
    ends=np.r_[ends,len(on)]
len(starts), len(ends), starts[:5], ends[:5]


(64,
 64,
 array([   89,  3465,  5153,  8529, 22033]),
 array([ 2443,  4131,  7507, 10883, 24387]))

Python

python
dur = (ends-starts)/fr
gap = (starts[1:]-ends[:-1])/fr
np.percentile(dur,[0,10,25,50,75,90,100]), np.percentile(gap,[0,10,25,50,75,90,100])


(array([0.06027149, 0.06027149, 0.06027149, 0.06027149, 0.21303167,
        0.21303167, 0.21303167]),
 array([0.09248869, 0.09248869, 0.09248869, 0.09248869, 1.00904977,
        1.00904977, 2.91855204]))

Python

python
np.unique(np.round(dur,3)), np.unique(np.round(gap,3))[:10], len(np.unique(np.round(gap,3)))


(array([0.06 , 0.213]), array([0.092, 1.009, 2.919]), 3)

Python

python
codes=[]
current=""
for i,sym in enumerate(symbols):
    current+=sym
    if i < len(gaps):
        g=gaps[i]
        if g<0.3:
            continue
        elif g<2.0:
            codes.append(current); current=""
        else:
            codes.append(current); codes.append(' '); current=""
if current: codes.append(current)
codes[:20], len(codes)


(['-.--',
  '---',
  '..-',
  '.-',
  '.--.',
  '---',
  '...',
  '.-.',
  '.',
  ' ',
  '..',
  '-.',
  ' ',
  '-',
  '....',
  '.',
  ' ',
  '.-.',
  '.-',
  '-...'],
 28)

Python

python
import struct, pathlib
b=pathlib.Path(wav_path).read_bytes()
# parse RIFF chunks
pos=0
riff=b[pos:pos+4]; pos+=4
size=struct.unpack('<I',b[pos:pos+4])[0]; pos+=4
wave=b[pos:pos+4]; pos+=4
chunks=[]
while pos+8<=len(b):
    cid=b[pos:pos+4]; pos+=4
    csize=struct.unpack('<I',b[pos:pos+4])[0]; pos+=4
    cdata=b[pos:pos+csize]; pos+=csize
    if csize%2==1: pos+=1
    chunks.append((cid.decode('ascii','ignore'),csize,pos))
    if cid==b'data':
        data_end=pos
        break
chunks, data_end, len(b)


([('fmt ', 16, 36), ('data', 477704, 477748)], 477748, 477748)

Pensiero

Focusing on the audio and possible steganographic hints

It looks like the audio contains just the Morse-coded message: “YOU'RE IN THE RABBIT HOLE”. The user might expect more, like hidden messages or steganography, suggesting we could mention it's encoded in Morse using the 1 kHz tone. We might also connect this to potential further exploration, like using VirusTotal.

Decoding and connecting clues

The user mentioned an "intelligence problem" earlier about the Malware_Search.VT.txt file, and now seems focused on the audio message. While the hash could link to VirusTotal, I should mention the connection between the audio message and further actions, like using the passphrase or examining the attached files for encryption details, especially considering their multiple inquiries.

Structuring the solution for decoding

The audio message likely contains a Morse code hidden in a 1kHz tone with particular timing for dots, dashes, and gaps. The decoded message is "YOUAPOSRE IN THE RABBIT HOLE", which we interpret as "YOU'RE IN THE RABBIT HOLE". I’ll clearly present these details with the exact timings and message for clarity and to guide the user’s understanding.

Providing decoding steps and code snippets

For decoding the message, I could suggest using Audacity's spectrogram view to measure tone durations, then decode based on the observed timings. Here's a minimal Python code snippet that might help too.

Since it's derived from a user-uploaded file, there's no need for file_search but I may mention the file path for clarity. Let me know how I can best assist with these details!

Thought for 5m 56s

Risposta

Yep — there is a hidden message in alice.wav, and it’s not speech.

What the sound is “saying”

The audio is basically a ~1 kHz tone being turned on/off in patterns. Those on/off bursts match Morse code timing:

  • short tone ≈ 0.06 s → dot (.)
  • long tone ≈ 0.213 s → dash (-)
  • short gap ≈ 0.092 s → gap inside a letter
  • medium gap ≈ 1.009 s → gap between letters
  • long gap ≈ 2.919 s → gap between words

Decoded message:

YOUAPOSRE IN THE RABBIT HOLE

That APOS is commonly used to mean an apostrophe ('), so it reads as:

✅ “YOU’RE IN THE RABBIT HOLE”

How to see it quickly (Audacity method)

  1. Open alice.wav in Audacity
  2. Switch track view to Spectrogram
  3. You’ll see the bright band around ~1000 Hz blinking on/off (those are the dots/dashes)

If you want to decode it programmatically

If you tell me whether you want a Python solution or a command-line one, I’ll paste a clean “copy/paste and run” script that extracts the Morse automatically (bandpass → envelope → threshold → timing → text).

Domanda

this is not related with any of upper problem..now help me with this one .this is a intelligence related problem

Domanda

where is the answer

Domanda

the answer will be something like KHASCTF{....} the other one you gave before is not right..give me the flag

Domanda

pass

please forget the above problems ..this is a new one and cryptography problem ..help me with the flag..don't waste time on previous one ..the flag looks like KHASCTF{....}

Domanda

alice.wav
bit_0.txt
bit_1.txt
bit_2.txt
bit_3.txt
bit_4.txt
bit_5.txt
bit_6.txt
bit_7.txt

help me with this one

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