抛物线焦点轨迹
बनाया गया: 1 फ़रवरी 2025
का उपयोग करके उत्तर दिया गया O3 Mini High द्वारा Chat01
बनाया गया: 1 फ़रवरी 2025
का उपयोग करके उत्तर दिया गया O3 Mini High द्वारा Chat01
已知过点 A(−1,0) 、 B(1,0) 两点的动抛物线的准线始终与圆 x2+y2=9 相切,该抛物线焦点 P 的轨迹是某圆锥曲线 E 的一部分。<br>(1) 求曲线 E 的标准方程;<br>(2) 已知点 C(−3,0) , D(2,0) ,过点 D 的动直线与曲线 E 相交于 M 、 N ,设 △CMN 的外心为 Q , O 为坐标原点,问:直线 OQ 与直线 MN 的斜率之积是否为定值,如果为定值,求出该定值;如果不是定值,则说明理由。
Piecing together
OK, let me see. The problem asks for the standard equation of curve E, which appears to be a conic section, given a moving parabola with a specific directrix and points through which it passes.
Setting up the equation
I'm gathering info on a family of parabolas tangent to a circle at a specific directrix. The focus P traces a conic section E, making me think about the locus formed by the focus.
Charting distances
OK, I’m thinking about how the focus P and directrix L are tied to the circle x^2+y^2=9. The directrix is always tangential to this circle.
Setting up tangency
I’m setting the directrix L parameter to ensure it remains tangent to circle x^2+y^2=9, maintaining a distance of 3 from the center.
Determining relationships
I’m examining how the distances between points on the parabola and the directrix can be linked, which should help me simplify the expressions by eliminating variables like n, l, and m.
Investigating symmetry
I’m digging into symmetry properties of parabolas, particularly focusing on points A and B being equidistant from the focus and directrix, which might simplify deriving relationships for the parabola's equation.
Analyzing symmetry
I’m gathering insights on the symmetry of parabolas with respect to the y-axis, especially concerning points A and B and their midpoint, to establish the parabola's vertex.
Formulating relationships
Equating expressions for distances from points on the parabola to the focus and directrix. This reveals crucial equations that help identify the parabola's characteristics.
Clarifying distance relationships
I’m refining the distance relationships between the focus, directrix, and points on the parabola to ensure clarity and continuity in understanding their geometric properties.
Reflecting points
Considering the reflection of points across the directrix to derive relationships between the focus and the parabola, I aim to explore the symmetry and geometric properties of the parabola.
Analyzing distance equality
I'm working through the geometric properties of parabolas, deriving a relationship between the focus and directrix using distances, leading to the equation h=−(l2+m2)ln.
Adjusting my approach
I’m recalculating relationships involving the focus and directrix, expressing them through trigonometric terms like cosθ, to refine the equation for h and explore k.
Piecing together distance
I’m working through the distances from the focus to the directrix and points on the parabola, comparing squared distances to derive a relation for h and explore potential expressions for k.
Investigating symmetry
I'm examining how the symmetry of a parabola, with points A and B equidistant from the directrix, affects the axis of symmetry and potential relationships among the focus, directrix, and parabola.
Focusing on axis symmetry
I’m thinking through how the symmetry of points A and B relative to the y-axis could indicate that the parabola's axis of symmetry is either vertical or horizontal.
Determining directrix alignment
I’m concluding that the directrix, tangent to a circle with a 3-unit radius, must be horizontal. This confirms the parabola's symmetry and its relationship with the directrix.
Investigating distance relationships
I’m thinking about the distance from points A and B to the directrix, ensuring they align with the parabola's symmetry and the directrix's tangency to a circle with a 3-unit radius.
Piecing together equations
I’m working through the equation 4h=−4ln/(l2+m2), using l=Rcosθ and m=Rsinθ to solve for h and decide the correct sign.
Weighing possibilities
I'm comparing the two scenarios for h and k by setting n/R=±3. This involves considering the distance from the parabola's focus to the directrix.
Deriving k
I’m calculating k by comparing equations for A and B, simplifying to k=±(22sinθ) and deciding the appropriate sign.
Mapping the locus
I’m noting that k can be ±22sinθ, leading to a locus of two curves. This ensures the focus aligns with the parabola's symmetry and the directrix.
Piecing together E's shape
Piecing together the locus of F with h=−3cosθ and k=±22sinθ, it suggests an ellipse or hyperbola.
Confirming consistency
OK, let me see. By checking both n=3R and n=−3R, it’s clear that the locus equation x2/9+y2/8=1 aligns with the parabola's definition.
Verifying the equation
I’m piecing together that x2/9+y2/8=1 is the correct locus of the focus P, confirmed by testing key angles θ.
Verifying the equation
I’m checking if x2/9+y2/8=1 represents an ellipse and determining the product of slopes of lines OQ and MN through points on the ellipse.
Piecing together slopes
I found the product of slopes OQ and MN to be constant as ∥t∥18. This crucial link simplifies understanding the relationship between the ellipse and its surroundings.
Piecing together intersections
I’m figuring out the intersection points M and N by ensuring x=2 isn’t a solution, confirming their distinctness on the ellipse. This leads me to understand their precise locations.
Equations in play
I’m gathering info on two methods to compute the circumcenter Q of triangle CMN, including using perpendicular bisectors or reflections, considering the points C, M, and N on the ellipse.
Laying out options
I’m gathering info on identifying the circumcenter Q of triangle CMN using perpendicular bisectors, radical axis, and symmetry in the context of the ellipse.
Taking a closer look
I’m working through the perpendicular bisectors of MN and CM to pinpoint Q. Considering D's presence on MN and the chord's shape through the ellipse adds depth to the analysis.
Figuring out the midpoint
I’m working through the midpoint of MN using S and P from the quadratic equation, then considering Q on the perpendicular bisector of MN. This helps identify Q's position.
Calculating Q's coordinates
Taking a closer look, I equate squared distances from Q to C and M, then eliminate λ to express Q in terms of t and the ellipses' coordinates.
Investigating circumcenter theories
I’m considering properties of chords and reflections in the conic, aiming to find connections between the slopes of OQ and MN, possibly leading to a constant product of slopes.
Pinpointing the circle's center
I'm setting up the equation for the triangle's circumscribed circle, passing through points C, M, and N, to locate the circle's center Q.
Connecting equations
I’m linking the slopes of OQ and MN with E and D through their intersection on the radical axis of the ellipse and circle. This helps analyze their relationship.
Ensuring clarity
I’m working through the radical axis of the circle and ellipse, ensuring it aligns with their intersecting chord MN, and refining the equation for accurate results.
Figuring out circumcenter
I’m gathering info on Q's coordinates, noticing it lies on the perpendicular bisector of MN and is equidistant from C and MN's midpoint, to efficiently pinpoint Q.
Ensuring intersection
I’m confirming Q intersects the perpendicular bisectors of both CM and MN by applying the slopes and midpoint coordinates, ensuring Q's alignment with these conditions.
Implementing reflection
Reflecting C over MN and using the midpoint of segment CC′ helps me identify the circumcenter of triangle CMN, streamlining the location of Q.
Mapping out reflections
I'm thinking through how reflecting C over MN reveals that C,M,N,C′ lie on a circle with MN as the chord and CC′ as the diameter.
Determining circumcenter
I'm calculating the circumcenter Q using the formula with coordinates of C,M, and N. This involves the intersection of perpendicular bisectors and determinants.
Piecing together
I’m setting up the circumcenter Q in terms of the coordinates of C,M, and N. Using determinants and perpendicular bisectors, I calculate Q's x coordinate as u.
Simplifying the expression
I'm working through the numerator of the circumcenter u with x coordinates of C,M, and N. Noticing symmetry might streamline the expression in terms of S.
Refining the expression
I’m sharpening the expression for u. It seems to be a difference quotient, possibly hinting at a derivative application or a more streamlined determinant-based formula for the circumcenter.
Piecing together details
Interestingly enough, C as an endpoint of the ellipse's major axis hints at a geometric relationship, possibly simplifying the circumcenter calculation by leveraging this familiar ellipse property.
Mapping out possibilities
I'm considering if the circumcenter Q is tied to the ellipse's center or involves inversion. Also, exploring if Q is the midpoint of an arc or the intersection of perpendicular bisectors.
Figuring out the link
I’m mapping out if Q on the perpendicular bisector of MN relates to the distance from Q to C. Considering QC as QM might work well.
Connecting concepts
Now I'm thinking about how Q is the circumcenter of △CMN and aligns with points on the ellipse. Using the radical axis formula might reveal more with known points.
Piecing together
OK, let me see. By applying the radical axis concept, I can derive the circle through points C, M, and N from their intersections with the ellipse.
Thinking geometrically
I'm piecing together the product of slopes of OQ and MN could reveal a connection with the ellipse's center, using inversion or homothety.
Taking a closer look
I’m working through different t values to understand the slope of MN. For t=0, M and N coincide, making the triangle △CMN degenerate.
Calculating intersections
I’m figuring out where the line y=x−2 meets the ellipse, leading to intersection points M and N. Then, I’ll pinpoint the circumcenter Q of △CMN.
Piecing it together
I'm gathering info on the circumcenter formula, calculating slopes and coordinates, and working through the intersection points to pinpoint the exact circumcenter of △CMN.
Simplifying calculations
I'm stripping away redundancies and leveraging x1−x2 to streamline the numerator for the circumcenter. This helpfully reduces the complexity of the expression.
Crafting the approach
I’m working out the x-coordinate u=−5/34 for the circumcenter Q and calculating the v-coordinate using a perpendicular bisector relation to pinpoint Q's exact location.
Adjusting my approach
I’m analyzing how slopes and intersections change with t=2. This involves solving quadratic equations and revisiting the determination of the u-coordinate for the circumcenter.
Revisiting derivation
OK, let me see. I’m reworking the numerator for the circumcenter formula, using u=−1/[2(x1−x2)]⋅[9Δx+2PΔx−8Δx+4Δx].
Calculating u and v
I’m finding the u-coordinate for the circumcenter by analyzing slopes and intersections. Then, I’m working out v using distance formulas to pinpoint the circumcenter’s exact location.
Calculating v-coordinate
Using determinants and perpendicular bisector, combined with u and t, I determined v=t(S/2−2)+(S/2−u)/t for the circumcenter.
Adjusting my approach
I’m recalculating u with a quadratic formula for S and P, followed by solving v using a perpendicular bisector equation, and simplifying expressions to clarify the process.
Revisiting slopes
I'm examining the slopes of lines OQ and MN, focusing on their product. This helps determine if the expression remains constant as t changes, which is quite interesting to see.
Evaluating proportionality
I’m checking if the product of slopes 40−45t249t2−40 hints at a constant. It turns out this product changes with t, showing no constant trend.
Reflecting on consistency
I checked if the product of slopes 40−45t249t2−40 holds constant. The evidence suggests no fixed value, though inaccuracies in calculations remain a possibility.
Analyzing geometric patterns
I’m exploring the relationship between an ellipse, line L, points C and D, and the circumcenter Q to determine if the product of slopes of OQ and MN is constant.
Recalculating and testing
I’m recalculating Q for t=1 and t=2 to ensure the coordinates are accurate and the slopes and relationships are clearly defined.
Confirming accuracy
I verified u and v for t=2, calculated the slope of OQ, and checked the product of slopes of OQ and MN, which is not constant.
Confirming circumcenter formula
I’m refining the circumcenter formula for triangle OAB by recalculating the denominator, ensuring the slopes of OQ and MN are properly determined and consistent.
Revealing connections
I’m examining how Q lies on the perpendicular bisector of MN, with a slope of −1/t, thanks to Q's geometric attributes.
Revisiting geometric relations
I’m rethinking the product of slopes and considering the geometric relationship between the ellipse's vertices and the circle with a diameter from the ellipse vertex to the opposite vertex again.
Determining Q's locus
I’m mapping out that Q is on the perpendicular bisectors of MN and CM, using their midpoints and slopes, and noting its equidistance to C and T.
Determining the product's dependency
I determined that the expression for the product of slopes, (49t2−40)/(40−45t2), is not constant, as the numerator and denominator are not proportional.
Reassessing constants
I’m re-evaluating if the product of slopes remains constant by re-reading the problem statement in Chinese, focusing on verifying if the expression results in a constant.
Verifying variables
I’m confirming S and P by substituting y=t(x−2) into the ellipse equation. The product of slopes should simplify to a constant.
Connecting points
I'm pulling together that Q, as the circumcenter of triangle CMN, is equidistant from C and any point on MN, and it lies on the perpendicular bisector of CM.
Applying circumcenter formula
I’m piecing together the circumcenter formula for a triangle to find Q, using coordinates A,B, and C, and simplifying the expression to determine X.
Piecing together Y
I’m expressing Y in terms of t by combining terms and simplifying, ultimately determining Y as 2t(8+9t2)−40+81t2+4t2(8+9t2) after thorough simplification.
Ensuring consistency
I’m focusing on the product of slopes staying constant by confirming the expression (49t2−40)/(40−45t2) remains equivalent to −(49t2−40)/(45t2−40).
Unveiling inconsistency
Interestingly enough, the product of slopes (49t2−40)/(40−45t2) isn't constant. This suggests that the circumcenter Q isn't perfectly aligned with the family of lines MN, causing the angle between OQ and MN to shift.
Confirming the relationship
OK, let me see. The equation x2/9+y2/8=1 represents the family of ellipses. The slope product (49t2−40)/(40−45t2) isn't constant due to t's involvement.
Thought about 轨迹与准线问题 for 3m 5s
我们下面给出一种较为几何‐代数的解法,其主要思路是:首先求出满足条件的抛物线族的焦点轨迹,再研究过定点 D(2,0) 的直线与该轨线 E 的交点 M,N 所构成三角形 △CMN(其中 C(−3,0))的外心 Q 的坐标,并考察直线 OQ 与直线 MN(即该直线本身)的斜率乘积是否独立于参数。下面我们详细说明。
设一个抛物线的焦点为 P(p,q) ,准线为直线
ℓ:lx+my+n=0.由抛物线的定义,任一点 (x,y) 到焦点的距离等于到准线的距离,即
(x−p)2+(y−q)2=l2+m2(lx+my+n)2.该抛物线过定点 A(−1,0) 和 B(1,0) ,代入得
(p+1)2+q2=l2+m2(−l+n)2,(p−1)2+q2=l2+m2(l+n)2.把这两式相减,可以消去 q2:
(p+1)2−(p−1)2=l2+m2(−l+n)2−(l+n)2.注意左边有
(p+1)2−(p−1)2=4p.而右边利用
(−l+n)2−(l+n)2=−4ln,因此有
4p=−l2+m24ln⟹p=−l2+m2ln.另一方面,题中还要求该抛物线的准线始终与圆
x2+y2=9相切。已知圆的切线到圆心的距离等于半径,因此准线 ℓ 到原点的距离满足
l2+m2∣n∣=3⟹∣n∣=3l2+m2.我们可以取
n=3l2+m2或n=−3l2+m2.令
l=l2+m2cosθ,m=l2+m2sinθ,则上式写为
p=−l2+m2(l2+m2cosθ)(±3l2+m2)=∓3cosθ.再经进一步利用点 A (或 B )的方程,可以证明 q2=8sin2θ(正负号无碍于轨迹方程)。写成参数形式,即
p=±3cosθ,q=±22sinθ.消去参数 θ (注意 cos2θ=9p2 和 sin2θ=8q2,且 cos2θ+sin2θ=1)得到
9p2+8q2=1.记 x=p,y=q 得轨迹方程
9x2+8y2=1.因此,焦点 P 的运动轨迹是椭圆
E:9x2+8y2=1.现在,在椭圆 E 上取定动点。已知点 C(−3,0)(注意 C 恰好是椭圆 E 的左顶点)和点 D(2,0) 为固定点。过 D 作一动直线,其斜率记为参数 t,则直线方程写为
y=t(x−2).此直线与椭圆 E 的交点记为 M 和 N ,其 x 坐标为二次方程根。将 y=t(x−2) 代入
9x2+8y2=1得
9x2+8t2(x−2)2=1.乘以 72 得
8x2+9t2(x−2)2=72.整理后写成标准二次形式
(8+9t2)x2−36t2x+(36t2−72)=0.设其两根为 x1 和 x2,则中点坐标为
T(2x1+x2,2t[(x1−2)+(x2−2)])=(2S,t(2S−2)),其中
S=x1+x2=8+9t236t2.另一方面,证明三角形 △CMN 的外心 Q(即其三边的垂直平分线的交点)的坐标经过一番运算可以写成
Q=(2(8+9t2)40−45t2,2t(8+9t2)49t2−40).(这里的计算可采用利用三角形外心的行列式公式,也可先求出 MN 的中点及其垂直方向,再与 C 关于某边的垂直平分线联立求出 Q;详细计算略去。)
于是,直线 OQ(O(0,0))的斜率为
mOQ=QxQy=t(40−45t2)49t2−40.而直线 MN 的斜率正是 t(因为它就是 y=t(x−2))。
因此,它们斜率的乘积为
mOQ⋅t=40−45t249t2−40.显然,此表达式中含有 t(即直线的斜率参数),除非分子与分母关于 t2 恰成比例,否则它随 t 变化。事实上,若设
49t2−40=k(40−45t2)要求对所有 t 成立,则比较 t2 的系数得 49=−45k;而常数项得 −40=40k,这得到 k=−4040=−1,但代入前一式则要求 49=−45(−1)=45,矛盾。
因此,斜率乘积
mOQ⋅mMN=40−45t249t2−40依赖于参数 t(即直线 MN 的方向),不是常值。
(1) 焦点 P 的轨迹 E 的标准方程为
9x2+8y2=1.(2) 设过 D(2,0) 的直线斜率为 t(方程 y=t(x−2)),经过一番计算可得三角形 △CMN 的外心 Q 坐标为
Q=(2(8+9t2)40−45t2,2t(8+9t2)49t2−40),故有
mOQ⋅mMN=40−45t249t2−40,显然这个表达式依赖于 t;也就是说,直线 OQ 与直线 MN 的斜率之积不是定值。
利用抛物线经过定点以及准线切于圆的条件,可证明其焦点 P 运动在椭圆
9x2+8y2=1上。
对于过定点 D 的直线,其与 E 的交点 M,N 构成的 △CMN 的外心 Q 的坐标依赖于直线斜率 t;因此,直线 OQ 与 MN 的斜率乘积
40−45t249t2−40随 t 变化,不为定值。
这就是本题的答案与理由。