一根长5.5米的棍子能否通过一道高4米宽3米的门?

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سؤال

一根长5.5米的棍子能否通过一道高4米宽3米的门?

الفكرة

Considering the door and stick dimensions

The question seems like a classic puzzle: Can a 5.5-meter stick pass through a 3m by 4m door? I’m thinking this connects to the "ladder moving through a corner" problem, but here it's a straight door. The puzzle is very much geometry-based. I’ll need to think about the calculations or a formula related to this. The door is rectangular at 3m wide and 4m tall, while the stick is 5.5m long. Let me figure out the math for this!

Exploring the math behind the stick

I’m wondering if I can tilt the stick diagonally to pass it through the door. This is kind of like the "ladder moving around a corner" problem, but this time it's just a straight door. The typical formula for the longest object to fit through a rectangle uses the diagonal, which is sqrt(3^2 + 4^2) = 5. But the stick is 5.5 meters, so it doesn’t fit flat. Still, it might pass if angled, but this isn’t exactly like the ladder problem. Let me think further.

Analyzing the stick and door problem

This is similar to a classic puzzle: "Can a 5.5-meter ladder fit through a 3m by 4m door?" The answer is yes if it's tilted. With the stick, the trick is tilting it out of the door's plane. The maximum object length possible through the door is the diagonal of the door itself, which is 5m — but the stick is 5.5m. However, by rotating it in 3D, the stick’s projection could fit within the door's dimensions, making it passable. Interesting! Let me confirm the math on this.

Reasoned for 46 seconds

الإجابة

答案是可以的。

当棍子平放时,其所需通过的对角线长度为 √(3^2 + 4^2) = 5 米,而 5.5 米明显超过这一长度。但如果把棍子倾斜(即不完全平行于门面),其在门面上的投影长度就会变短。设棍子与门面之间的夹角为 θ,则投影长度为 5.5 × cosθ。只要选取一个 θ,使得 5.5 cosθ ≤ 5(例如,cosθ ≈ 5/5.5 ≈ 0.909,对应约 24°),就能使棍子的投影完全适合门的对角线,从而顺利通过门。

因此,只需适当旋转和倾斜,5.5 米长的棍子就能通过高 4 米、宽 3 米的门。

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